在正则表达式中使用反向引用来动态替换文本

我想像整数一样使用$ 1值。
我们的想法是使用等效的数组值替换originaltext中的所有数字并创建一个新文本。
下面想要的结果应该是“这是DBValue4，这是DBValue2，这是DBValue7”
另外，有没有办法保存这些反向引用以供进一步使用？

String[] values = {"DBValue0","DBValue1","DBValue2","DBValue3","DBValue4","DBValue5","DBValue6","DBValue7","DBValue8","DBValue9","DBValue10"}; String originaltext = "This is 4, This is 2, This is 7"; text = originaltext.replaceAll("(\\d)","$1"); // want something like text = originaltext.replaceAll("(\\d)",values[$1]); //or text = originaltext.replaceAll("(\\d)",values[Integer.parseInt("$1")]); 

Answer 1

您可以像这样使用Pattern和Matcher ：

 public static void main(String[] args) throws Exception { final String[] values = {"DBValue0", "DBValue1", "DBValue2", "DBValue3", "DBValue4", "DBValue5", "DBValue6", "DBValue7", "DBValue8", "DBValue9", "DBValue10"}; final String originaltext = "This is 4, This is 2, This is 7"; final Pattern pattern = Pattern.compile("(?<=This is )\\d++"); final Matcher matcher = pattern.matcher(originaltext); final StringBuffer sb = new StringBuffer(); while (matcher.find()) { System.out.println(matcher.group()); final int index = Integer.parseInt(matcher.group()); matcher.appendReplacement(sb, values[index]); } matcher.appendTail(sb); System.out.println(sb); } 

输出：

 4 2 7 This is DBValue4, This is DBValue2, This is DBValue7 

编辑

OP的注释似乎是OP需要替换{name, index}forms的String {name, index}其中“name”是数组的名称，“index”是该数组中元素的索引。

这可以通过使用Map将数组Map到其名称，然后使用首先捕获name然后捕获index的Pattern来轻松实现。

 public static void main(String[] args) throws Exception { final String[] companies = {"Company1", "Company2", "Company3"}; final String[] names = {"Alice", "Bob", "Eve"}; final String originaltext = "This is {company, 0}, This is {name, 1}, This is {name, 2}"; final Map values = new HashMap<>(); values.put("company", companies); values.put("name", names); final Pattern pattern = Pattern.compile("\\{([^,]++),\\s*+(\\d++)}"); final Matcher matcher = pattern.matcher(originaltext); final StringBuffer sb = new StringBuffer(); while (matcher.find()) { System.out.println(matcher.group(1)); System.out.println(matcher.group(2)); final int index = Integer.parseInt(matcher.group(2)); matcher.appendReplacement(sb, values.get(matcher.group(1))[index]); } matcher.appendTail(sb); System.out.println(sb); } 

输出：

 company 0 name 1 name 2 This is Company1, This is Bob, This is Eve