如何在Java中获取程序窗口的x和y？

有没有办法让我在java中获取窗口的X和Y值？ 我读到我将不得不使用运行时，因为java不能直接混乱，但我不太清楚如何做到这一点。 谁能指出一些关于如何获得这个的链接/提示？

Answer 1

要获得“任何其他无关应用程序”的x和y位置，您将不得不查询操作系统，这意味着可能使用JNI，JNA或其他一些脚本实用程序，如AutoIt（如果是Windows）。 我建议使用JNA或脚本实用程序，因为它们比JNI（我的经验有限）更容易使用，但要使用它们，您需要下载一些代码并将其与Java应用程序集成。

编辑1我不是JNA专家，但是我确实把它搞砸了，这就是我得到一些命名窗口的窗口坐标：

import java.util.Arrays; import com.sun.jna.*; import com.sun.jna.platform.win32.WinDef.HWND; import com.sun.jna.win32.*; public class GetWindowRect { public interface User32 extends StdCallLibrary { User32 INSTANCE = (User32) Native.loadLibrary("user32", User32.class, W32APIOptions.DEFAULT_OPTIONS); HWND FindWindow(String lpClassName, String lpWindowName); int GetWindowRect(HWND handle, int[] rect); } public static int[] getRect(String windowName) throws WindowNotFoundException, GetWindowRectException { HWND hwnd = User32.INSTANCE.FindWindow(null, windowName); if (hwnd == null) { throw new WindowNotFoundException("", windowName); } int[] rect = {0, 0, 0, 0}; int result = User32.INSTANCE.GetWindowRect(hwnd, rect); if (result == 0) { throw new GetWindowRectException(windowName); } return rect; } @SuppressWarnings("serial") public static class WindowNotFoundException extends Exception { public WindowNotFoundException(String className, String windowName) { super(String.format("Window null for className: %s; windowName: %s", className, windowName)); } } @SuppressWarnings("serial") public static class GetWindowRectException extends Exception { public GetWindowRectException(String windowName) { super("Window Rect not found for " + windowName); } } public static void main(String[] args) { String windowName = "Document - WordPad"; int[] rect; try { rect = GetWindowRect.getRect(windowName); System.out.printf("The corner locations for the window \"%s\" are %s", windowName, Arrays.toString(rect)); } catch (GetWindowRect.WindowNotFoundException e) { e.printStackTrace(); } catch (GetWindowRect.GetWindowRectException e) { e.printStackTrace(); } } } 

当然，为了实现这一点，需要下载JNA库并将其放在Java类路径或IDE的构建路径中。

Answer 2

在最终用户的帮助下，这很容易做到。 让他们点击屏幕截图中的一个点。

例如

 import java.awt.*; import java.awt.event.*; import java.awt.image.*; import javax.swing.*; /** Getting a point of interest on the screen. Requires the MotivatedEndUser API - sold separately. */ class GetScreenPoint { public static void main(String[] args) throws Exception { Robot robot = new Robot(); final Dimension screenSize = Toolkit.getDefaultToolkit(). getScreenSize(); final BufferedImage screen = robot.createScreenCapture( new Rectangle(screenSize)); SwingUtilities.invokeLater(new Runnable() { public void run() { JLabel screenLabel = new JLabel(new ImageIcon(screen)); JScrollPane screenScroll = new JScrollPane(screenLabel); screenScroll.setPreferredSize(new Dimension( (int)(screenSize.getWidth()/2), (int)(screenSize.getHeight()/2))); final Point pointOfInterest = new Point(); JPanel panel = new JPanel(new BorderLayout()); panel.add(screenScroll, BorderLayout.CENTER); final JLabel pointLabel = new JLabel( "Click on any point in the screen shot!"); panel.add(pointLabel, BorderLayout.SOUTH); screenLabel.addMouseListener(new MouseAdapter() { public void mouseClicked(MouseEvent me) { pointOfInterest.setLocation(me.getPoint()); pointLabel.setText( "Point: " + pointOfInterest.getX() + "x" + pointOfInterest.getY()); } }); JOptionPane.showMessageDialog(null, panel); System.out.println("Point of interest: " + pointOfInterest); } }); } } 

典型输出

 Point of interest: java.awt.Point[x=342,y=43] Press any key to continue . . .