如何在针对XML模式validationXML文件时获取错误的行号

我正在尝试针对W3C XML SchemavalidationXML。

以下代码执行作业并报告何时发生错误。 但是我无法得到错误的行号。 它总是返回-1。

有没有简单的方法来获得行号？

import java.io.File; import javax.xml.XMLConstants; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.transform.Source; import javax.xml.transform.dom.DOMSource; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.Schema; import javax.xml.validation.SchemaFactory; import javax.xml.validation.Validator; import org.w3c.dom.Document; import org.xml.sax.SAXParseException; public class XMLValidation { public static void main(String[] args) { try { DocumentBuilder parser = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document document = parser.parse(new File("myxml.xml")); SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Source schemaFile = new StreamSource(new File("myschema.xsd")); Schema schema = factory.newSchema(schemaFile); Validator validator = schema.newValidator(); validator.validate(new DOMSource(document)); } catch (SAXParseException e) { System.out.println(e.getLineNumber()); e.printStackTrace(); } catch (Exception e) { e.printStackTrace(); } } } 

Answer 1

我找到了这个

http://www.herongyang.com/XML-Schema/Xerces2-XSD-Validation-with-XMLReader.html

似乎提供以下详细信息（包括行号）

 Error: Public ID: null System ID: file:///D:/herong/dictionary_invalid_xsd.xml Line number: 7 Column number: 22 Message: cvc-datatype-valid.1.2.1: 'yes' is not a valid 'boolean' value. 

使用此代码：

 /** * XMLReaderValidator.java * Copyright (c) 2002 by Dr. Herong Yang. All rights reserved. */ import java.io.IOException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.XMLReaderFactory; import org.xml.sax.SAXException; import org.xml.sax.SAXParseException; class XMLReaderValidator { public static void main(String[] args) { String parserClass = "org.apache.xerces.parsers.SAXParser"; String validationFeature = "http://xml.org/sax/features/validation"; String schemaFeature = "http://apache.org/xml/features/validation/schema"; try { String x = args[0]; XMLReader r = XMLReaderFactory.createXMLReader(parserClass); r.setFeature(validationFeature,true); r.setFeature(schemaFeature,true); r.setErrorHandler(new MyErrorHandler()); r.parse(x); } catch (SAXException e) { System.out.println(e.toString()); } catch (IOException e) { System.out.println(e.toString()); } } private static class MyErrorHandler extends DefaultHandler { public void warning(SAXParseException e) throws SAXException { System.out.println("Warning: "); printInfo(e); } public void error(SAXParseException e) throws SAXException { System.out.println("Error: "); printInfo(e); } public void fatalError(SAXParseException e) throws SAXException { System.out.println("Fattal error: "); printInfo(e); } private void printInfo(SAXParseException e) { System.out.println(" Public ID: "+e.getPublicId()); System.out.println(" System ID: "+e.getSystemId()); System.out.println(" Line number: "+e.getLineNumber()); System.out.println(" Column number: "+e.getColumnNumber()); System.out.println(" Message: "+e.getMessage()); } } } 

Answer 2

尝试使用SAXLocator http://download.oracle.com/javase/1.5.0/docs/api/org/xml/sax/Locator.html解析器不需要提供，但如果他们这样做，应报告行号

我认为您的代码应包括：

  // this will be called when XML-parser starts reading // XML-data; here we save reference to current position in XML: public void setDocumentLocator(Locator locator) { this.locator = locator; } 

（见http://www.java-tips.org/java-se-tips/org.xml.sax/using-xml-locator-to-indicate-current-parser-pos.html ）

解析器将为您提供一个定位器，然后您可以使用该定位器来获取行号。 当发生这种情况时，可能值得打印/调试，看看你是否有一个有效的定位器

Answer 3

你可以抓住SaxException e 。 然后调用e.toString()

它会给出类似的东西：

org.xml.sax.SAXParseException; lineNumber：2668151; columnNumber：80; 除非用于标记CDATA部分的结尾，否则字符序列“]]>”不得出现在内容中。