如何在jsp中显示Json对象
我是jsp的新手。 我有一个JSON
编码
{"eventDetails":[{"startDate":1387175589253,"eventJSON":"{\"userIp\":\"***.***.***.**\",\"organizationUid\":\"4261-5404a609bd14\",\"userAgent\":\"Restlet-Framework\/2.1m3\",\"currentSessionToken\":\"9f3ee5b076-27dbead458ca\",\"endTime\":1312,\"apiKey\":\"b6bd9-30849cf17727\",\"startTime\":13853,\"sessionToken\":null,\"eventId\":\"4731d1-adb6-10faaa3ee269\",\"userUid\":null,\"userId\":1,\"context\":\"\/v2\/account\/loginas\/anonymous\",\"eventName\":\"user-loginAs\""
我需要将eventJSON对象显示为原始数据:
{\"userIp\":\"204.236.177.80\",\"organizationUid\":\"4261739e-ccae-11e1-adfb-5404a609bd14\",\"userAgent\":\"Restlet-Framework\/2.1m3\",\"currentSessionToken\":\"9f3ee54a-4f5f-b076-27d8ca\",\"endTime\":1387175589312,\"apiKey\":\"b6b8-4ad5-96d9-3084927\",\"startTime\":1387175589253,\"sessionToken\":null,\"eventId\":\"478e8-4ed1-adb6-10faaa3ee269\",\"userUid\":null,\"userId\":11878,\"context\":\"\/v2\/act\/lonas\/anonymous\",\"eventName\":\"user-loginAs\"}
如何使用gson显示eventJSON并使用c:out
打印。
JSP页面
Java的
Datalogging[] logevents = (Datalogging[]) gson.fromJson(eventValueList.toString(),Datalogging[].class);
谢谢阅读。
-
你有它像这样的JavaScript变量:
var persons = [{“name”:“John Doe”,“address”:“Main Street 1”},{“name”:“Jane Doe”,“address”:“Baker Street 1”},{“name” :“Jack Doe”,“地址”:“Church Street 1”}];
我建议使用jQuery从中创建一个HTML表。
Test
2.你将它作为Java String变量,如下所示:
String jsonPersons = "[" + "{ \"name\": \"John Doe\", \"address\": \"Main Street 1\" }," + "{ \"name\": \"Jane Doe\", \"address\": \"Baker Street 1\" }," + "{ \"name\": \"Jack Doe\", \"address\": \"Church Street 1\" }" + "]";
然后我建议使用JSON解析器从中获取List,例如Google Gson:
List persons = new Gson().fromJson(jsonPersons, new TypeToken>() {}.getType());
Person类看起来像这样:
public class Person { private String name; private String address; // Add or generate getters/setters. }
让servlet将它放在请求范围内并转发到JSP进行显示,如下所示:
request.setAttribute("persons", persons); request.getRequestDispatcher("/WEB-INF/persons.jsp").forward(request, response);
在JSP中,使用JSTL迭代它:
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %> ... ${person.name} ${person.address}
3与2)相同,您将它作为Java变量,但您希望通过JSP中的Ajax获取它。 然后创建一个Servlet类,它在doGet()方法中执行以下操作:
response.setCharacterEncoding("UTF-8"); response.setContentType("application/json"); response.getWriter().write(jsonPersons);
并通过jQuery Ajax调用它,其回调与1)相同。
$(document).ready(function() { var table = $('
').appendTo($('#somediv')); $.getJSON('url/to/servlet', function(persons) { persons.each(function(i, person) { $(' ').appendTo(table) .append($(' ').text(person.name)) .append($(' ').text(person.address)); }); }); });