如何使用SentiWordNet获取String或形容词的语义方向

我正在做一个关于情绪分析的项目。 我需要字符串或形容词的语义方向，所以我建议使用Stackoverflow“如何使用SentiWordNet”的参考文章中的SentiWordNet_3.0.0。我运行了代码，但每次得到以下输出。

java.lang.ArrayIndexOutOfBoundsException: 2 at qtag.SWN3.(SWN3.java:29) at qtag.SWN3.main(SWN3.java:105) 0.0 

我已经使用不同的字符串作为输入运行代码，但结果是相同的。 我已经删除了SentiWordNet_3.0.0_20130122.txt文件的第一部分或垃圾部分。我的代码有什么问题。我该怎么办呢？ 请帮帮我。 谢谢。 这是我的代码：

 import java.io.BufferedReader; import java.io.FileReader; import java.util.HashMap; import java.util.Iterator; import java.util.Set; import java.util.Vector; public class SWN3 { private String pathToSWN = "C:/Users/Monalisa/Desktop/SentiWordNet_3.0.0/home/swn/www/admin/dump/SentiWordNet_3.0.0_20130122.txt"; private HashMap_dict; public SWN3(){ _dict = new HashMap(); HashMap<String, Vector> _temp = new HashMap<String, Vector>(); try{ BufferedReader csv = new BufferedReader(new FileReader(pathToSWN)); String line = ""; while((line = csv.readLine()) != null) { String[] data = line.split("\t"); Double score = Double.parseDouble(data[2])-Double.parseDouble(data[3]); String[] words = data[4].split(" "); for(String w:words) { String[] w_n = w.split("#"); w_n[0] += "#"+data[0]; int index = Integer.parseInt(w_n[1])-1; if(_temp.containsKey(w_n[0])) { Vector v = _temp.get(w_n[0]); if(index>v.size()) for(int i = v.size();i<index; i++) v.add(0.0); v.add(index, score); _temp.put(w_n[0], v); } else { Vector v = new Vector(); for(int i = 0;i<index; i++) v.add(0.0); v.add(index, score); _temp.put(w_n[0], v); } } } Set temp = _temp.keySet(); for (Iterator iterator = temp.iterator(); iterator.hasNext();) { String word = iterator.next(); Vector v = _temp.get(word); double score = 0.0; double sum = 0.0; for(int i = 0; i < v.size(); i++) score += ((double)1/(double)(i+1))*v.get(i); for(int i = 1; i=0.75) sent = "strong_positive"; else if(score > 0.25 && score 0 && score>=0.25) sent = "weak_positive"; else if(score =-0.25) sent = "weak_negative"; else if(score =-0.5) sent = "negative"; else if(score<=-0.75) sent = "strong_negative"; _dict.put(word, score); } } catch(Exception e){e.printStackTrace();} } public Double extract(String word) { Double total = new Double(0); if(_dict.get(word+"#n") != null) total = _dict.get(word+"#n") + total; if(_dict.get(word+"#a") != null) total = _dict.get(word+"#a") + total; if(_dict.get(word+"#r") != null) total = _dict.get(word+"#r") + total; if(_dict.get(word+"#v") != null) total = _dict.get(word+"#v") + total; return total; } public static void main(String[] args) { SWN3 test = new SWN3(); String sentence="what a super great day"; String[] words = sentence.split("\\s+"); double totalScore = 0; for(String word : words) { word = word.replaceAll("([^a-zA-Z\\s])", ""); if (test.extract(word) == null) continue; totalScore += test.extract(word); } System.out.println(totalScore); } } 

Answer 1

我希望您已经从sentiwordnet（sentiwordnet.isti.cnr.it）上的给定示例中获取了源代码。 所以问题出在sentiwordnet_3.0.0_20130122.txt“文件……它应该从第一个形容词开始，所以删除所有的评论….最后有一些额外的空间删除它们。所以简而言之第一行应该是文件的开头

**a 00001740 0.125 0 able#1 (usually followed by to) having the necessary means or skill or know-how or authority to do something; "able to swim"; "she was ........**

以及最后一行应该是文件的结尾

**v 02772310 0.125 0 deflagrate#1 cause to burn rapidly and with great intensity; "care must be exercised when this substance is to be deflagrated"**

除此之外，我认为应该是错误，但要纠正它
private HashMap _dict ;