从Java字节中提取半字节

Hex:[0A][52][08][01][01][01][00][CD][21][02][59] 0 [0A] 1 [52] Packettype = TEMP_HUM 2 [08] subtype = TH8 - 3 [01] Sequence nbr = 1 4/5 [01][01] ID = 257 6/7 [00][CD] Temperature = 20.5 °C 8 [21] Humidity = 33 9 [02] Status = Dry 10 [5] *nibble Signal level = 5 11 [9] *nibble Battery = OK 

所以我通过串口获得了11个字节（Hex）。 我将所有字节分配给一个字节数组，以便我以后可以使用它们。

我有两个问题：

1]如何在Java中将4和5字节组合在一起（我假设在INT中）？ 2]如何提取最后一个字节的10和11或高和低半字节？

[来自下面的评论]示例字节：高[0110]低lowNibble = yourbyte＆0x0f; 01010110＆0x0f（00001111）= 00000110

  highNibble = yourByte >>>> 4 01010110 >>> 4 = 00000101 IF you use this Example Byte: High[1101][0110]Low highNibble = yourByte >>> 4 11010110 >>> 4 = 00000101 Because >>> removes the signed bit. 

Answer 1

1）这取决于字节顺序。 它将是(b[4] << 8) | b[5] (b[4] << 8) | b[5]或(b[5] << 8) | b[4] (b[5] << 8) | b[4]

2） lowNibble = yourByte & 0x0f; highNibble = (yourByte >> 4) & 0x0f; lowNibble = yourByte & 0x0f; highNibble = (yourByte >> 4) & 0x0f;

你也可以这样做： lowNibble = yourByte & 0x0f; highNibble = yourByte >>> 4; lowNibble = yourByte & 0x0f; highNibble = yourByte >>> 4;

无符号移位（ >>> ）将高位填充为零，无论符号如何。