“更改java版本后，路径login.page不以”/“字符”消息exception开头

我有一个Web应用程序，它使用以下内容：Tomcat 5.0 Struts 1.0 Java 1.5

我必须切换到Java 1.6。当我尝试这样做时，我在浏览器中收到以下exception堆栈：

javax.servlet.ServletException: Path login.page does not start with a "/" character org.apache.struts.chain.ComposableRequestProcessor.process(ComposableRequestProcessor.java:286) org.apache.struts.action.ActionServlet.process(ActionServlet.java:1913) org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:449) javax.servlet.http.HttpServlet.service(HttpServlet.java:743) javax.servlet.http.HttpServlet.service(HttpServlet.java:856) org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:72) org.apache.jasper.runtime.PageContextImpl.doForward(PageContextImpl.java:712) org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:682) org.apache.jsp.index_jsp._jspService(index_jsp.java:45) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:133) javax.servlet.http.HttpServlet.service(HttpServlet.java:856) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:311) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248) javax.servlet.http.HttpServlet.service(HttpServlet.java:856) org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:78) org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:77) 

根本原因

 java.lang.IllegalArgumentException: Path login.page does not start with a "/" character org.apache.struts.chain.commands.servlet.PerformForward.handleAsForward(PerformForward.java:107) org.apache.struts.chain.commands.servlet.PerformForward.perform(PerformForward.java:96) org.apache.struts.chain.commands.AbstractPerformForward.execute(AbstractPerformForward.java:54) org.apache.struts.chain.commands.ActionCommandBase.execute(ActionCommandBase.java:51) org.apache.commons.chain.impl.ChainBase.execute(ChainBase.java:190) org.apache.commons.chain.generic.LookupCommand.execute(LookupCommand.java:304) org.apache.commons.chain.impl.ChainBase.execute(ChainBase.java:190) org.apache.struts.chain.ComposableRequestProcessor.process(ComposableRequestProcessor.java:283) org.apache.struts.action.ActionServlet.process(ActionServlet.java:1913) org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:449) javax.servlet.http.HttpServlet.service(HttpServlet.java:743) javax.servlet.http.HttpServlet.service(HttpServlet.java:856) org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:72) org.apache.jasper.runtime.PageContextImpl.doForward(PageContextImpl.java:712) org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:682) org.apache.jsp.index_jsp._jspService(index_jsp.java:45) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:133) javax.servlet.http.HttpServlet.service(HttpServlet.java:856) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:311) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248) javax.servlet.http.HttpServlet.service(HttpServlet.java:856) org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:78) org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:77) 

Answer 1

它似乎是对"login.page"的请求，如exception所示，它不以"/"开头。 请尝试申请"/login.page" 。

大多数servlet库要求路径名以"/"开头。 例如： javax.servlet.ServletContext＃getRequestDispatcher ：

路径名必须以"/"开头，并且被解释为相对于当前上下文根。 使用getContext为外部上下文中的资源获取RequestDispatcher 。

Answer 2

查看此页面。

http://wiki.apache.org/struts/StrutsUpgradeNotes12to13

显然你正在使用stuts tiles。 如果您使用的是Struts 1.3，则应将其添加到您的web.xml文件中：

  chainConfig org/apache/struts/tiles/chain-config.xml  

Answer 3

添加tile请求处理器类并从controller标签中删除conten type属性