检测java中的回车键
我试图用扫描仪获取用户输入，如果用户按Enter键，则继续下一个输入语句。 但它会立刻打印出来。
public class MainRDS { public static void main(String[] args) { Scanner in = new Scanner(System.in); String path; String name; String ext; String date; System.out.println("Directory search by path, name, extension, content and date."); System.out.print("\nEnter Starting directory for the search (link c:"+"\\"+"temp) : "); path = in.next(); System.out.print("\nEnter the file name (like myFile or enter for all) : "); if((name = in.nextLine()).length() > 0) System.out.print("\nEnter the file extenstion (like txt or enter for all) : "); if((ext = in.nextLine()).length() > 0) System.out.print("\nEnter last modified date (like 11/21/2012 or enter for any) : "); date = in.nextLine(); } } 输出：
Directory search by path, name, extension, content and date. Enter Starting directory for the search (link c:\temp) : c: Enter the file name (like myFile or enter for all) : myfile Enter last modified date (like 11/21/2012 or enter for any) :
所需产量：
Directory search by path, name, extension, content and date. Enter starting directory for the search (like c:\temp): c:\temp Enter the file name (like myFile or enter for all): Enter the file extension (like txt or enter for all): txt Enter content to search for (like comp121 or enter for any): Enter last modified date (like 11/21/2013 or enter for any): 11/1/2011
你的代码非常好。你只需要更换你的第一行
Scanner in = Scanner(System.in);
同
Scanner in =new Scanner(System.in);
我无法理解你是如何测试这段代码的，因为这不是一个正在运行的代码，因为Scanner in = Scanner(System.in); 这条线
得到它了！
你需要使用：
path = in.nextLine();
否则， name = in.nextLine()捕获路径的“enter”键，但不会获得任何值。
我刚刚测试了你的代码，它确实让用户按下“回车”键。你能解释一下你在寻找更具体的内容吗？ 正如其他人所说，只需更改您的扫描仪：
Scanner in = new Scanner(System.in);
更改
path = in.next();
至
path = in.nextLine();
经过测试，所有打印出来并且工作正常！