用Java绘制线条

我怎么画这样的java图？

这是我的代码，必须至少绘制这个数字的一​​半

import java.awt.Color; import java.awt.Graphics; import javax.swing.JComponent; import javax.swing.JFrame; public class Main { public static void main(String[] a) { JFrame window = new JFrame(); window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); window.setBounds(30, 30, 300, 300); window.getContentPane().add(new MyCanvas()); window.setVisible(true); } } class MyCanvas extends JComponent { private static final long serialVersionUID = 1L; public void paint(Graphics g) { int i =0; for ( i = 0; i < 100; i++) { int x=1+i*3; g.drawLine(x, 200, 2+(x+(i/2)), 400-((i*i)/20)); } } } 

我得到了这个。

Answer 1

一个小动画，向您展示您需要在线旋转方面寻找的逻辑。 把这条线想象成一只手上的钟。 如何在时钟上动画一只手。 这几乎是完全相同的概念。 唯一的区别是x1 （时钟指针中心点的x点），而不是保持静止，它在手转动时沿x轴（即y1常数）移动。 因此，对于时钟的每个刻度（手动旋转），x位置也水平移动。 这就是我看待它的方式。

 import java.awt.Color; import java.awt.Dimension; import java.awt.Graphics; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.util.ArrayList; import java.util.List; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.Timer; public class Main { public static void main(String[] a) { JFrame window = new JFrame(); window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); window.setResizable(false); window.getContentPane().add(new MyCanvas()); window.pack(); window.setVisible(true); } } class MyCanvas extends JPanel { int x1 = 0; int rotate = 50; List lines; Timer timer = null; public MyCanvas() { lines = new ArrayList<>(); timer = new Timer(75, new ActionListener() { public void actionPerformed(ActionEvent e) { if (rotate < -50) { ((Timer) e.getSource()).stop(); } else { lines.add(new Line(x1, rotate)); repaint(); x1 += 5; rotate--; } } }); JButton start = new JButton("Start the Magic"); start.addActionListener(new ActionListener(){ public void actionPerformed(ActionEvent e) { timer.start(); } }); add(start); } public Dimension getPreferredSize() { return new Dimension(502, 400); } private static final long serialVersionUID = 1L; public void paintComponent(Graphics g) { super.paintComponent(g); g.setColor(Color.BLACK); g.fillRect(0, 0, getWidth(), getHeight()); for (Line line : lines) { line.drawLine(g); } } class Line { int x1; int rotate; int y1 = 200; public Line(int x1, int rotate) { this.x1 = x1; this.rotate = rotate; } void drawLine(Graphics g) { int Radius = (int) (Math.min(getWidth(), getHeight()) * 0.4); int sLength = (int) (Radius * 0.9); int xSecond = (int) (x1 + sLength * Math.sin(rotate * (2 * Math.PI / 100))); int ySecond = (int) (y1 - sLength * Math.cos(rotate * (2 * Math.PI / 100))); g.setColor(Color.GREEN); g.drawLine(x1, y1, xSecond, ySecond); } } } 

Answer 2

我这么多：D

  float centerY = 250; float x1 = 0; float x2 = 0; float y2 = 400; float way2 = 0; for (int i = 0; i < 125; i++) { x2 += cos(way2*PI/-180)*10; y2 += sin(way2*PI/-180)*10; way2 += centerY/y2*0.235*10; x1 += y2/600*10; g.drawLine(x1,centerY,x2,y2); } 

Answer 3

这是我想出来的，尽管有点不同:)

  public void paint(Graphics g) { for (int i = 0; i < 100; i++) { int x = 1 + i * 3; g.drawLine(x, 200, x + i, 400 - i * i / 20); g.drawLine(600 - x, 200, 600 - (x + i), 400 - i * i / 20); } } 

我们需要修改function'400 - i * i / 20'。