通过URL调用Java中的PHP文件

我正在尝试开发一个Android应用程序，它调用一个php文件来查询和从数据库中提取数据。 URL可以通过Web浏览器在我的手机上访问，但我似乎无法从下面的java代码中调用它。 任何人都可以帮助我从我的Java代码调用我的PHP文件。

URL url = new URL("http://10.0.3.2/MYCODE/app/login.php"); String urlParams = "name="+name+"&password="+password; HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection(); httpURLConnection.setDoOutput(true); OutputStream os = httpURLConnection.getOutputStream(); os.write(urlParams.getBytes()); os.flush(); os.close(); InputStream is = httpURLConnection.getInputStream(); while((tmp=is.read())!=-1){ data+= (char)tmp; } is.close(); httpURLConnection.disconnect(); 

我收到以下错误： java.io.FileNotFoundException:

我正在使用POST方法，因为它更安全。

Answer 1

如果它是GET方法，那么我们可以使用下面的代码行，你的调用文件的问题可能是你的.php文件路径不正确

  //Integrating url with values [Starts] Map request = new HashMap(); request.put("name", name); request.put("password", password); Uri.Builder uriBuilder = new Uri.Builder(); uriBuilder.encodedPath("http://10.0.3.2/MYCODE/app/login.php"); if (mapOfStrings != null) { for (Map.Entry entry : request.entrySet()) { Log.d("buildSanitizedRequest", "key: " + entry.getKey() + " value: " + entry.getValue()); uriBuilder.appendQueryParameter(entry.getKey(), entry.getValue()); } } String uriString; try { uriString = uriBuilder.build().toString(); // May throw an // UnsupportedOperationException } catch (Exception e) { Log.e("Exception", "Exception" + e); } //Integrating url with values [Ends] HttpURLConnection connection = null; try { URL url = new URLuriBuilder.build().toString()); connection = (HttpURLConnection) url.openConnection(); connection.setRequestProperty("Content-Type", "application/json"); connection.setRequestProperty("Accept", "application/json"); connection.setRequestProperty("Accept-Charset", "utf-8,*"); Log.d("Get-Request", url.toString()); try { BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(connection.getInputStream())); StringBuilder stringBuilder = new StringBuilder(); String line; while ((line = bufferedReader.readLine()) != null) { stringBuilder.append(line).append("\n"); } bufferedReader.close(); Log.d("Get-Response", stringBuilder.toString()); return new JSONObject(stringBuilder.toString()); } finally { connection.disconnect(); } } catch (Exception e) { Log.e("ERROR", e.getMessage(), e); return null; }` 

Answer 2

请确保Manifest和WIFI中的以下两行已启用并连接到子网10.0.3.x.

如果获得post方法，那么“？” 在你的url？

Answer 3

你可以在这个方法中使用URL url = new URL("http://localhost/test.php?print=success"); URLConnection connection = url.openConnection(); connection.connect(); URL url = new URL("http://localhost/test.php?print=success"); URLConnection connection = url.openConnection(); connection.connect();

同样这个我用于我的一个项目这cluesshop.com