Java multidimensional Array to string和String to Array

我有arrays

data[][]; 

转换为字符串：

 string = Arrays.deepToString(data); 

串：

 [[1, 1394119227787, 59474093, USD/DKK, true, 0.05, 5.391582, 5.00663, 5.39663, null, null], [1, 1394581174413, 59500543, EUR/JPY, false, 0.05, 142.489381, 145.3, 139.68, null, null], [1, 1394581174413, 59500543, EUR/JPY, false, 0.05, 142.489381, 145.3, 139.68, null, null], [1, 1394581174413, 59500543, EUR/JPY, false, 0.05, 142.489381, 145.3, 139.68, null, null]] 

以及如何将此字符串转换回数组？

Answer 1

尝试我的stringToDeep（）方法转换回Array。

 import java.util.*; public class DeepToArray { public static void main(String[] args) { int row, col; row = 2; col = 3; String[][] in = new String[row][col]; for (int i = 0; i < row; i++) { for (int j = 0; j < col; j++) { in[i][j] = i + " " + j; } } String str = Arrays.deepToString(in); System.out.println(str); String[][] out = stringToDeep(str); for (String s2[] : out) { for (String s3 : s2) { System.out.print(s3 + " "); } System.out.println(); } } private static String[][] stringToDeep(String str) { int row = 0; int col = 0; for (int i = 0; i < str.length(); i++) { if (str.charAt(i) == '[') { row++; } } row--; for (int i = 0;; i++) { if (str.charAt(i) == ',') { col++; } if (str.charAt(i) == ']') { break; } } col++; String[][] out = new String[row][col]; str = str.replaceAll("\\[", "").replaceAll("\\]", ""); String[] s1 = str.split(", "); int j = -1; for (int i = 0; i < s1.length; i++) { if (i % col == 0) { j++; } out[j][i % col] = s1[i]; //System.out.println(s1[i] + "\t" + j + "\t" + i % col); } return out; } } 

Answer 2

java API中没有任何方法可以自动将其转换回数组。 您可以自己编写代码来执行此操作，但这会很棘手; 此格式不会转义特殊字符，如方括号或逗号。 使用专为编码和解码数组而设计的格式（如JSON）可能更容易。

Answer 3

数组到字符串并返回到数组：P

 import java.util.Arrays; import java.util.Random; public class arrays { public static void main(String [ ] args) { String[][] in = new String [10][4]; String[][] out = new String [10][4]; arrays nr = new arrays(); for(int i =0; i< 4; i++){ for(int j =0; j< 4; j++){ in[i][j] = nr.Rand(5); } } System.out.println(Arrays.deepToString(in)); // tablica ok // convert array to string String line = ""; for(int i =0; i< 4; i++){ for(int j =0; j< 4; j++){ line += in[i][j] + "_"; } line += ":"; } System.out.println(line); // line back to array String[] xline = line.split(":"); int ss = 0; for (String str : xline) { out[ss] = (String[]) str.split("_"); System.out.println("string line>>>" + str); ss++; } System.out.println(Arrays.deepToString(out)); } public String nextSessionId() { //private SecureRandom random = new SecureRandom(); //return new BigInteger(130, random).toString(32); return null; } public String Rand(int zz){ char[] chars = "987654321abcdefghijklm111nopqrstuvwxyz0123456789".toCharArray(); StringBuilder sb = new StringBuilder(); Random random = new Random(); for (int i = 0; i < zz; i++) { char c = chars[random.nextInt(chars.length)]; sb.append(c); } String output = sb.toString(); // System.out.println(output); return output; } } 

：d

Answer 4

我发现的所有答案都只是二维的，所以这是我的解决方案，可以为任意数量的维度反转deepToString（…）：

用法示例：

 String arrString = "[[[0.11695497071135137, 0.8830064157596283, 0.3433854446148375, 0.18825445694298526, 1.0441938749175883, 0.8941633746325311], [-0.089908138214512, 0.39821330927870574, 0.1365997500579524, 0.7008902956765364, 0.9897596683277262, 0.2847717055995359], [0.6450670283688857, 0.01516064860567864, -0.07904927386204857, 0.2703900981351612, 0.45402985012492075, 0.30505608337251183], [0.5122943117220898, 0.008726346575469023, 0.7734611917871235, 0.3051772999891666, 0.5237487372571624, 1.1824105144656751]]]"; String arr = (String[][][]) reverseDeepToString(arrString); System.out.println(Arrays.deepToString(arr)); 

此代码将字符串（ arrString ）转换为数组，然后函数Arrays.deepToString(...)将其转换回相同的字符串。

function代码：

 public static Object reverseDeepToString(String str){ int dimensions = 0; for(int x = 0; x < str.length(); x++) if(str.charAt(x) == '[') dimensions++; else break; str = str.substring(dimensions, str.length() - dimensions); return createArrayRecursive(str, dimensions); } private static Object createArrayRecursive(String str, int dimension){ if(dimension == 1) return str.split(", "); // modify the code here if you want to convert the strings to another variable type String[] s = str.split(getArraySeparator(dimension)); int[] lengths = new int[dimension]; lengths[0] = s.length; Object arr = Array.newInstance(String.class, lengths); // and here (see comment above) for(int x = 0; x < s.length; x++) Array.set(arr, x, createArrayRecursive(s[x], dimension - 1)); return arr; } private static String getArraySeparator(int dimension){ String separator = ", "; for(int x = 1; x < dimension; x++) separator = ']' + separator + "\\["; return separator; }