twitter4j没有发现身份validation挑战

一直试图使用twitter4j发布推文几天没有运气，我想做的是让一个人在一轮结束时从应用程序在他们的时间轴上发布新的最高分。 这是我的代码

@Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_tweetr); Button tweetr = (Button)findViewById(R.id.tweetr); //create a new twitter configuration using user details tweetTwitter = new TwitterFactory().getInstance(); tweetTwitter.setOAuthConsumer(TWIT_KEY, TWIT_SECRET); //create a twitter instance // tweetTwitter = new TwitterFactory(twitConf).getInstance(); tweetr.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { dt.execute(); } }); } public class TweetTask extends AsyncTask { @Override protected String doInBackground(Object... values) { /* try { //requestToken = tweetTwitter.getOAuthRequestToken(TWITTER_CALLBACK_URL); } catch (TwitterException e) { // TODO Auto-generated catch block e.printStackTrace(); } startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(requestToken.getAuthenticationURL()))); */ try { requestToken = tweetTwitter.getOAuthRequestToken(TWITTER_CALLBACK_URL); String authUrl = requestToken.getAuthenticationURL(); startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(authUrl))); } catch (TwitterException e) { // TODO Auto-generated catch block e.printStackTrace(); } return null; } @Override protected void onPostExecute(String result) { Log.d("URI", "DONE"); super.onPostExecute(result); } } @Override protected void onResume() { super.onResume(); final Uri uri = getIntent().getData(); if(uri != null ){ Log.d("URI", uri.toString()); Thread th = new Thread(){ public void run(){ try { String verifier = uri.getQueryParameter("oauth_verifier"); String oauthToken = uri.getQueryParameter("oauth_token"); RequestToken reqToken = tweetTwitter.getOAuthRequestToken(oauthToken,verifier); AccessToken accessToken = tweetTwitter.getOAuthAccessToken(reqToken); String token = accessToken.getToken(), secret = accessToken.getTokenSecret(); } catch (TwitterException ex) { Log.e("Main.onNewIntent", "" + ex.getMessage()); } }}; th.start(); }else Log.d("URI", "FAILED"); } 

}

这是我的错误打印输出

 10-23 15:35:18.661: D/TWIT ER(2392): No authentication challenges foundRelevant discussions can be found on the Internet at: 

Answer 1

请参考Twitter4J的javadoc

 In order to get access acquire AccessToken using xAuth, you must apply by sending an email to [e-mail] — all other applications will receive an HTTP 401 error.