单个socket.IO连接android中的所有活动

我在这里为SocketIOClient引用创建了Singleton类。 服务器已连接。 我可以将活动请求发送到SocketIOClient。 但是如何在Activity中获得Singleton类的响应？

我的活动：

import java.net.MalformedURLException; import org.json.JSONException; import org.json.JSONObject; import android.app.Activity; import android.os.Bundle; import android.view.Menu; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.Toast; public class MainActivity extends Activity { EditText uname, passwd; Button login; JSONObject json; SocketIOClient socket; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); socket = new SocketIOClient(); try { SocketIOClient.initInstance(); } catch (MalformedURLException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } json = new JSONObject(); uname = (EditText) findViewById(R.id.unameED); passwd = (EditText) findViewById(R.id.passwdED); login = (Button) findViewById(R.id.loginButton); login.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub try { json.put("username", uname.getText().toString().trim()); json.put("password", passwd.getText().toString().trim()); //request send to server SocketIOClient.emit("login_request", json); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } } }); } } 

我的Singleton类也有on（）方法：

  @Override public void on(String event, IOAcknowledge ack, Object... args) { JSONArray jarr_args = new JSONArray(); JSONObject jobj_in = new JSONObject(); if (event.equals("registration_status")) { jarr_args.put(args[0]); try { jobj_in = jarr_args.getJSONObject(0); Log.d("Result", jobj_in.getString("result")); if (jobj_in.getString("result").equals("success")) { } else { Log.d("check:", "username and password"); } } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } 

Singleton类可以从服务器获得响应。 但我想知道，如何在我的活动中得到回应？

Answer 1

像这样创建一个抽象类

 public abstract class ResponseHandler { private Context context; public abstract void execute (JSONObject jsonObject) throws JSONException; public ResponseHandler (Context ctx) { this.context = ctx; } public void handleObject(JSONObject jsonObject) throws Exception { execute(jsonObject); } } 

在您的活动中调用socket类时，也将ResponseHadler作为参数传递示例：

 SocketIOClient.initInstance(your parameters, new ResponseHandler(this) { //ResponseHandler have an abstract method called execute(). So you are overriding it here @Override public void execute(JSONObject jsonObject) throws JSONException { // Here you will get your JSONObject passed from socket class } } 

在你的socket类中

 public class YourSocketClass { private ResponseHandler handler; public static void initInstance(your parameter, ResponseHandler responseHandler) { this.handler = responseHandler; // Do your operations here } @Override public void on(String event, IOAcknowledge ack, Object... args) { JSONArray jarr_args = new JSONArray(); JSONObject jobj_in = new JSONObject(); if (event.equals("registration_status")) { jarr_args.put(args[0]); try { jobj_in = jarr_args.getJSONObject(0); Log.d("Result", jobj_in.getString("result")); if (jobj_in.getString("result").equals("success")) { //If you want to pass your jsonobject from here to activity //Do something like this handler.handleObject(jobj_in); } else { Log.d("check:", "username and password"); } } catch (JSONException e) { e.printStackTrace(); } } } }