“java.net.MalformedURLException：未找到协议”读取到html文件
我收到了一个错误： java.net.MalformedURLException: Protocol not found
我想在网上阅读一个HTML文件
mainfest ::::: uses-permission android:name="android.permission.INTERNET" uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" import com.doviz.R.id; import android.os.Bundle; import android.app.Activity; import android.view.Menu; import android.widget.TextView; import android.widget.Toast; public class MainActivity extends Activity { public String inputLine; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); String myUri = ""; myUri = "www.tcmb.gov.tr/kurlar/today.html"; Toast.makeText( this, "step-1 " , Toast.LENGTH_LONG).show(); try{ Toast.makeText( this, "step -2" , Toast.LENGTH_LONG).show(); myUri = "www.tcmb.gov.tr/kurlar/today.html"; URL url = new URL(myUri); Toast.makeText( this, "step-3" , Toast.LENGTH_LONG).show(); final InputStream is =url.openStream(); Toast.makeText( this, "step -4" , Toast.LENGTH_LONG).show(); BufferedReader reader = new BufferedReader(new InputStreamReader(is)); Toast.makeText( this, "step -5 " , Toast.LENGTH_LONG).show(); String line; Toast.makeText( this, "step-6" , Toast.LENGTH_LONG).show(); while ((line=reader.readLine())!=null){ // page.add(line); } Toast.makeText( this, " step-7" , Toast.LENGTH_LONG).show(); } catch(Exception e){ //e.printStackTrace(); TextView tx =(TextView)findViewById(id.TextView1); tx.setText(myUri + " >>> "+ e.getMessage()); Toast.makeText( this, "problem = " + e.getMessage() + " -- "+ e.getLocalizedMessage(), Toast.LENGTH_LONG).show(); //System.exit(1); } Toast.makeText( this, "step -8" , Toast.LENGTH_LONG).show(); }
您的URI不是URI。 没有协议组件。 它需要http：//或您想要的任何其他协议。
String myUri = ""; myUri = "www.tcmb.gov.tr/kurlar/today.html";
你的uri没有完成。你可以写完整的url。
String myUri="https://www.tcmb.gov.tr/kurlar/today.html";