android从maps.google.com指示获取持续时间

目前我正在使用此代码查询谷歌地图以查找从地址到另一个地址的路线，然后我只是从其GeometryCollection的mapview上绘制它。 但这还不够，我还需要从kml中提取总预期持续时间。 有人可以提供一些示例代码来帮助我吗？ 谢谢

StringBuilder urlString = new StringBuilder(); urlString.append("http://maps.google.com/maps?f=d&hl=en"); urlString.append("&saddr=");//from urlString.append( Double.toString((double)src.getLatitudeE6()/1.0E6 )); urlString.append(","); urlString.append( Double.toString((double)src.getLongitudeE6()/1.0E6 )); urlString.append("&daddr=");//to urlString.append( Double.toString((double)dest.getLatitudeE6()/1.0E6 )); urlString.append(","); urlString.append( Double.toString((double)dest.getLongitudeE6()/1.0E6 )); urlString.append("&ie=UTF8&0&om=0&output=kml"); //Log.d("xxx","URL="+urlString.toString()); // get the kml (XML) doc. And parse it to get the coordinates(direction route). Document doc = null; HttpURLConnection urlConnection= null; URL url = null; try { url = new URL(urlString.toString()); urlConnection=(HttpURLConnection)url.openConnection(); urlConnection.setRequestMethod("GET"); urlConnection.setDoOutput(true); urlConnection.setDoInput(true); urlConnection.connect(); dbf = DocumentBuilderFactory.newInstance(); db = dbf.newDocumentBuilder(); doc = db.parse(urlConnection.getInputStream()); if(doc.getElementsByTagName("GeometryCollection").getLength()>0) { //String path = doc.getElementsByTagName("GeometryCollection").item(0).getFirstChild().getFirstChild().getNodeName(); String path = doc.getElementsByTagName("GeometryCollection").item(0).getFirstChild().getFirstChild().getFirstChild().getNodeValue() ; //Log.d("xxx","path="+ path); String[] pairs = path.split(" "); String[] lngLat = pairs[0].split(","); // lngLat[0]=longitude lngLat[1]=latitude lngLat[2]=height // src GeoPoint startGP = new GeoPoint((int)(Double.parseDouble(lngLat[1])*1E6),(int)(Double.parseDouble(lngLat[0])*1E6)); mMapView01.getOverlays().add(new MyOverLay(startGP,startGP,1)); GeoPoint gp1; GeoPoint gp2 = startGP; for(int i=1;i<pairs.length;i++) // the last one would be crash { lngLat = pairs[i].split(","); gp1 = gp2; // watch out! For GeoPoint, first:latitude, second:longitude gp2 = new GeoPoint((int)(Double.parseDouble(lngLat[1])*1E6),(int)(Double.parseDouble(lngLat[0])*1E6)); mMapView01.getOverlays().add(new MyOverLay(gp1,gp2,2,color)); //Log.d("xxx","pair:" + pairs[i]); } mMapView01.getOverlays().add(new MyOverLay(dest,dest, 3)); // use the default color } }catch (MalformedURLException e){ e.printStackTrace(); }catch (IOException e){ e.printStackTrace(); }catch (SAXException e){ e.printStackTrace(); } catch (ParserConfigurationException e) { e.printStackTrace(); } } 

Answer 1

使用新的路线 api。 持续时间在响应中返回，不再解析KML，我认为无论如何都会破坏Google地图许可条款。

更新。 好的，使用JSON输出，解析内置于Android中。

例如

回应是

 { "status": "OK", "routes": [ { "summary": "I-40 W", "legs": [ { "steps": [ { "travel_mode": "DRIVING", "start_location": { "lat": 41.8507300, "lng": -87.6512600 }, "end_location": { "lat": 41.8525800, "lng": -87.6514100 }, "polyline": { "points": "a~l~Fjk~uOwHJy@P", "levels": "B?B" }, "duration": { "value": 19, "text": "1 min" }, "html_instructions": "Head \u003cb\u003enorth\u003c/b\u003e on \u003cb\u003eS Morgan St\u003c/b\u003e toward \u003cb\u003eW Cermak Rd\u003c/b\u003e", "distance": { "value": 207, "text": "0.1 mi" } }, ... ... additional steps of this leg ... ... additional legs of this route "duration": { "value": 74384, "text": "20 hours 40 mins" }, "distance": { "value": 2137146, "text": "1,328 mi" }, "start_location": { "lat": 35.4675602, "lng": -97.5164276 }, "end_location": { "lat": 34.0522342, "lng": -118.2436849 }, "start_address": "Oklahoma City, OK, USA", "end_address": "Los Angeles, CA, USA" } ], "copyrights": "Map data ©2010 Google, Sanborn", "overview_polyline": { "points": "a~l~Fjk~uOnzh@vlbBtc~@tsE`vnApw{A`dw@~w\\|tNtqf@l{Yd_Fblh@rxo@b}@xxSfytAblk@xxaBeJxlcBb~t@zbh@jc|Bx}C`rv@rw|@rlhA~dVzeo@vrSnc}Axf]fjz@xfFbw~@dz{A~d{A|zOxbrBbdUvpo@`cFp~xBc`Hk@nurDznmFfwMbwz@bbl@lq~@loPpxq@bw_@v|{CbtY~jGqeMb{iF|n\\~mbDzeVh_Wr|Efc\\x`Ij{kE}mAb~uF{cNd}xBjp]fulBiwJpgg@|kHntyArpb@bijCk_Kv~eGyqTj_|@`uV`k|DcsNdwxAott@r}q@_gc@nu`CnvHx`k@dse@j|p@zpiAp|gEicy@`omFvaErfo@igQxnlApqGze~AsyRzrjAb__@ftyB}pIlo_BflmA~yQftNboWzoAlzp@mz`@|}_@fda@jakEitAn{fB_a]lexClshBtmqAdmY_hLxiZd~XtaBndgC", "levels": "BBBAAAAABAABAAAAAABBAAABBAAAABBAAABABAAABABBAABAABAAAABABABABBABAABB" }, "warnings": [ ], "waypoint_order": [ 0, 1 ] } ] } 

假设您使用了标准的http客户端库，现在在String中有响应。

 JSONObject jsonObject = new JSONObject(response); // parse response into json object JSONObject routeObject = jsonObject.getJSONObject("route"); // pull out the "route" object JSONObject durationObject = jsonObject.getJSONObject("duration"); // pull out the "duration" object String duration = durationObject.getString("text"); //this should be the duration text value (20 hours 40 mins) 

您必须将所有这些包装在try-catch块中以捕获JSONExceptions 。