Ksoap：将用户定义的类作为参数传递给Web方法时，无法序列化exception

我花了几天时间试图找出如何使我的用户定义的java类可序列化，以便我可以将它作为参数发送到android ksoap调用c＃web方法。 下面是我的代码和调用webservice时在logcat中抛出的exception，如果我得到即时答复或帮助，我将感激不尽。

我的java类XY.java ：

 import org.ksoap2.serialization.KvmSerializable; import org.ksoap2.serialization.PropertyInfo; public class XY implements KvmSerializable { public static Class XY_CLASS = XY.class; private String MyNum; private String OppPhoneNum; private String Name; public XY() { } public XY(String MyNum, String Name, String oppNum) { this.MyNum = MyNum; this.Name = Name; this.OppPhoneNum = oppNum; } public String getPhoneNum() { return MyNum; } public void setPhoneNum(String MyNum) { this.MyNum = MyNum; } public String getName() { return Name; } public void setName(String Name) { this.Name = Name; } public String getOpponentPhoneNum() { return OppPhoneNum; } public void setOpponentPhoneNum(String OppPhoneNum) { this.OppPhoneNum = OppPhoneNum; } @Override public Object getProperty(int arg0) { switch(arg0) { case 0: return MyNum; case 1: return OppPhoneNum; case 2: return Name; } return null; } @Override public int getPropertyCount() { // TODO Auto-generated method stub return 3; } @Override public void getPropertyInfo(int index, Hashtable arg1, PropertyInfo info) { switch(index) { case 0: info.type = PropertyInfo.STRING_CLASS; info.name = "MyNum"; break; case 1: info.type = PropertyInfo.STRING_CLASS; info.name = "OppPhoneNum"; break; case 2: info.type = PropertyInfo.STRING_CLASS; info.name = "Name"; break; default:break; } } @Override public void setProperty(int index, Object value) { switch(index) { case 0: MyNum = value.toString(); break; case 1: OppPhoneNum = value.toString(); break; case 2: Name = value.toString(); break; default: break; } } } 

C＃等价类：

 [Serializable] public class XY { public System.String Name { get; set; } public System.String MyNum { get; set; } public System.String OppPhoneNum { get; set; } } 

这就是我从我的活动中使用kso​​ap调用服务的方式：

 private void unKnown(List entries) { //Initialize soap request + add parameters SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); PropertyInfo entriesProp =new PropertyInfo(); entriesProp.setName("entries"); entriesProp.setValue(entries); entriesProp.setType(ArrayList.class); //Use this to add parameters request.addProperty(entriesProp); //Declare the version of the SOAP request SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.setOutputSoapObject(request); envelope.addMapping(NAMESPACE, "XY", XY.XY_CLASS); envelope.dotNet = true; try { HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); //this is the actual part that will call the webservice androidHttpTransport.call(SOAP_ADDCONTACTS, envelope); // Get the SoapResult from the envelope body. if (envelope.bodyIn instanceof SoapFault) { String str= ((SoapFault) envelope.bodyIn).faultstring; Log.i("", str); } else { SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn; if(resultsRequestSOAP != null) { Log.i("AddContacts", "Adding Contacts succeeded"); } } } catch (Exception e) { e.printStackTrace(); } }** 

Logcatexception：

 java.lang.RuntimeException: Cannot Serialize: [XY .....** 

注意：我正在尝试将XY对象列表作为参数传递给Web服务方法。 我将不胜感激任何帮助 。

Answer 1

我编辑了我的示例并为您添加了新的完整示例，我认为它可以帮助您。 在这个例子中，我在服务器端数据库中有一个customer表，我想通过KvmSerializable用户定义的类将android中的数据插入到该表中。 以下是客户的KvmSerializable用户定义类：

 public class Customer implements KvmSerializable { public int Customer_ID; public String Customer_Name; public String Customer_Family; public Customer() { } public Customer(int customer_id, String customer_name, String customer_family) { Customer_ID = customer_id; Customer_Name = customer_name; Customer_Family = customer_family; } public Object getProperty(int arg0) { // TODO Auto-generated method stub switch (arg0) { case 0: return Customer_ID; case 1: return Customer_Name; case 2: return Customer_Family; } return null; } public int getPropertyCount() { // TODO Auto-generated method stub return 25; } public void getPropertyInfo(int index, Hashtable arg1, PropertyInfo info) { // TODO Auto-generated method stub switch (index) { case 0: info.type = PropertyInfo.INTEGER_CLASS; info.name = "Customer_ID"; break; case 1: info.type = PropertyInfo.STRING_CLASS; info.name = "Customer_Name"; break; case 2: info.type = PropertyInfo.STRING_CLASS; info.name = "Customer_Family"; break; default: break; } } public void setProperty(int index, Object value) { // TODO Auto-generated method stub switch (index) { case 0: Customer_ID = Integer.parseInt(value.toString()); break; case 1: Customer_Name = value.toString(); break; case 2: Customer_Family = value.toString(); break; default: break; } } } 

现在c＃用户定义的客户类：

  public class Customer { public int Customer_ID; public string Customer_Name; public string Customer_Family; } 

这是我为通过以下方式发送KvmSerializable对象而定义的CallSoap类：

 public class CallSoap { public static String NAMESPACE = "http://127.0.0.1:80/"; public static String URL = "http://127.0.0.1:80/service.asmx?WSDL"; public static Customer[] customers; public static int AddCustomer(Customer[] customers) { String MethodName = "AddCustomer"; SoapObject soapAddCustomer = new SoapObject(NAMESPACE, MethodName); //customers Parameter SoapObject soapDetails = new SoapObject(NAMESPACE, "customers"); SoapObject soapDetail[] = new SoapObject[customers.length]; for (int i=0;i 

最后是服务器端的AddCustomer方法：

 [WebMethod] public int AddCustomer(Customer[] customers) { for(int i=0;i 

Answer 2

我认为validation是正确的例子是不完整的。 您必须对对象’soapDetail’（CallSoap类）执行某些操作，将其添加到对象’soapDetails’或其他内容，因为如果我没有发送空数组。

编辑：

迭代器上缺少这行代码来完成Majid Daei Nejad示例：

 soapDetails.addSoapObject(soapDetail[i]);