使用java NodeList合并xml文件
我正在尝试合并两个xml文件，如下所示，但我无法获得所需的输出请帮助我谢谢
Java代码：
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setIgnoringComments(true); DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse(new File("file1.xml")); Document doc1 = builder.parse(new File("file2.xml")); NodeList nodes = doc.getElementsByTagName("staff"); NodeList nodes1 = doc1.getElementsByTagName("staff"); for(int i=0;i<nodes1.getLength();i=i+1){ Node n= (Node) doc.importNode(nodes1.item(i), true); nodes.item(i).getParentNode().appendChild(n); } Transformer transformer = TransformerFactory.newInstance().newTransformer(); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); StreamResult result = new StreamResult(new StringWriter()); DOMSource source = new DOMSource(doc); transformer.transform(source, result); Writer output = null; output = new BufferedWriter(new FileWriter("mergedxml.xml")); String xmlOutput = result.getWriter().toString(); output.write(xmlOutput); output.close(); System.out.println("merge complete"); File1.xml
john 465456433 gmail1
File2.xml
area1 city1
当前输出：
john 465456433 gmail1 area1 city1
预期产出：
john 465456433 gmail1 area1 city1
为了自己做到这一点。 你应该这样做：
public static void mergeXML(){ DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = null; Document doc = null; Document doc2 = null; try { db = dbf.newDocumentBuilder(); doc = db.parse(new File("D:\\Loic_Workspace\\Test2\\res\\test.xml")); doc2 = db.parse(new File("D:\\Loic_Workspace\\Test2\\res\\test2.xml")); NodeList ndListFirstFile = doc.getElementsByTagName("staff"); Node nodeArea = doc.importNode(doc2.getElementsByTagName("area").item(0), true); Node nodeCity = doc.importNode(doc2.getElementsByTagName("city").item(0), true); ndListFirstFile.item(0).appendChild(nodeArea); ndListFirstFile.item(0).appendChild(nodeCity); TransformerFactory tFactory = TransformerFactory.newInstance(); Transformer transformer = tFactory.newTransformer(); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); DOMSource source = new DOMSource(doc); StreamResult result = new StreamResult(new StringWriter()); transformer.transform(source, result); Writer output = new BufferedWriter(new FileWriter("D:\\Loic_Workspace\\Test2\\res\\testFinal.xml")); String xmlOutput = result.getWriter().toString(); output.write(xmlOutput); output.close(); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (TransformerException e) { // TODO Auto-generated catch block e.printStackTrace(); } }
testFinal.xml的最终输出：
john 465456433 gmail1 area1 city1
如你所愿;-)
希望能帮助到你，
此解决方案适用于需要在合并之前进行迭代和validation的文件。
file1.xml：
07402 irreversible 15666 07756 03063 irreversible 00916 04712
file2.xml：
00001 polyphosphate polyphosphohydrolase Polyphosphate + n H2O <=> (n+1) Oligophosphate 00002 Reduced ferredoxin:dinitrogen oxidoreductase (ATP-hydrolysing) 16 ATP + 16 H2O + 8 Reduced ferredoxin <=> 8 e- + 16 Orthophosphate + 16 ADP + 8 Oxidized ferredoxin 03063 cephalosporin-C:2-oxoglutarate aminotransferase Cephalosporin C + 2-Oxoglutarate <=> (7R)-7-(5-Carboxy-5-oxopentanoyl)aminocephalosporinate + D-Glutamate 07402 (7R)-7-(4-carboxybutanamido)cephalosporanate amidohydrolase (7R)-7-(4-Carboxybutanamido)cephalosporanate + H2O <=> 7-Aminocephalosporanic acid + Glutarate
为result.xml
07402 irreversible 15666 07756 (7R)-7-(4-carboxybutanamido)cephalosporanate amidohydrolase (7R)-7-(4-Carboxybutanamido)cephalosporanate + H2O <=> 7-Aminocephalosporanic acid + Glutarate 03063 irreversible 00916 04712 cephalosporin-C:2-oxoglutarate aminotransferase Cephalosporin C + 2-Oxoglutarate <=> (7R)-7-(5-Carboxy-5-oxopentanoyl)aminocephalosporinate + D-Glutamate
Java程序执行此操作：
import java.io.BufferedWriter; import java.io.File; import java.io.FileWriter; import java.io.StringWriter; import java.io.Writer; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.transform.OutputKeys; import javax.xml.transform.Transformer; import javax.xml.transform.TransformerFactory; import javax.xml.transform.dom.DOMSource; import javax.xml.transform.stream.StreamResult; import org.w3c.dom.Document; import org.w3c.dom.Node; import org.w3c.dom.NodeList; public class MergeXML { public static void main(String[] args) { MergeXML m = new MergeXML(); try { DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db; db = dbf.newDocumentBuilder(); Document secondaryMetabolismXML = db .parse(new File("/home/bioinfo/workspace/teste/src/file1.xml")); Document generalMetabolismXML = db .parse(new File("/home/bioinfo/workspace/teste/src/file2.xml")); NodeList secondaryReactions = secondaryMetabolismXML.getElementsByTagName("reaction"); NodeList generalReactions = generalMetabolismXML.getElementsByTagName("reaction"); for (int s = 0; s < secondaryReactions.getLength(); s++) { Node secondaryReaction = secondaryReactions.item(s); for (int g = 0; g < generalReactions.getLength(); g++) { Node generalReaction = generalReactions.item(g); if (getChildrenByNodeName(secondaryReaction, "ID").getTextContent() .equals(getChildrenByNodeName(generalReaction, "ID").getTextContent())) { if (getChildrenByNodeName(generalReaction, "reactionName") != null) { secondaryReaction.appendChild(secondaryMetabolismXML .importNode(getChildrenByNodeName(generalReaction, "reactionName"), true)); } if (getChildrenByNodeName(generalReaction, "reactionAlternativeName") != null) { secondaryReaction.appendChild(secondaryMetabolismXML.importNode( getChildrenByNodeName(generalReaction, "reactionAlternativeName"), true)); } if (getChildrenByNodeName(generalReaction, "reactionDescription") != null) { secondaryReaction.appendChild(secondaryMetabolismXML .importNode(getChildrenByNodeName(generalReaction, "reactionDescription"), true)); } } } } TransformerFactory tFactory = TransformerFactory.newInstance(); Transformer transformer = tFactory.newTransformer(); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); DOMSource source = new DOMSource(secondaryMetabolismXML); StreamResult result = new StreamResult(new StringWriter()); transformer.transform(source, result); Writer output = new BufferedWriter( new FileWriter("/home/bioinfo/workspace/teste/src/Result.xml")); String xmlOutput = result.getWriter().toString(); output.write(xmlOutput); output.close(); } catch (Exception e) { e.printStackTrace(); } } /** * Returns a node child when you have a match with a given node name * * @param node * @param nodeName * @return */ public static Node getChildrenByNodeName(Node node, String nodeName) { for (Node childNode = node.getFirstChild(); childNode != null;) { Node nextChild = childNode.getNextSibling(); if (childNode.getNodeName().equalsIgnoreCase(nodeName)) { return childNode; } childNode = nextChild; } return null; } }
问题是，你想将子元素附加到“staff”元素，但你实际做的是：
nodes.item(i).getParentNode().appendChild(n);
这意味着您正在寻找列表中某个“staff”节点的父节点，该节点是“company”。 因此，您要将新的“staff”节点（从doc1导入的节点）附加到doc的“company”节点
现在，您要做的是迭代doc1的“staff”子节点，并将它们逐个附加到doc的“staff”节点。 所以你想要更改nodes1定义如下：
// Retrieving child nodes of first "staff" element of doc1 NodeList nodes1 = doc1.getElementsByTagName("staff").item(0).getChildNodes();
然后通过替换更改您追加的节点
nodes.item(i).getParentNode().appendChild(n);
通过
nodes.item(0).appendChild(n);
所以现在你要将doc1的所有“staff”子节点（/！\仅用于第一个“staff”元素）附加到doc的第一个“staff”元素
注1：不要使用迭代变量（i）来运行列表A来选择另一个列表的项目，除非你知道你正在做什么（例如两个列表的长度相同）
注意2：该解决方案将doc1的第一个“staff”元素的节点附加到doc的第一个“staff”元素。 您可能希望在此处添加一些迭代。