如何从Java客户端处理服务器端HTTP文件上载
我想将文件从客户端上传到服务器。
客户端：Java使用HTTP post Server：Java Servlet
我在这里添加了客户端编码。 但是，我对服务器端处理没有任何想法。 请帮我一个代码片段。
private String Tag = "UPLOADER"; private String urlString = "http://192.168.42.140:8080/sampweb"; HttpURLConnection conn; String exsistingFileName = "/sdcard/log.txt"; String lineEnd = "\r\n"; String twoHyphens = "--"; String boundary = "*****"; try { // ------------------ CLIENT REQUEST Log.e(Tag, "Inside second Method"); FileInputStream fileInputStream = new FileInputStream(new File( exsistingFileName)); // open a URL connection to the Servlet URL url = new URL(urlString); // Open a HTTP connection to the URL conn = (HttpURLConnection) url.openConnection(); // Allow Inputs conn.setDoInput(true); // Allow Outputs conn.setDoOutput(true); // Don't use a cached copy. conn.setUseCaches(false); // Use a post method. conn.setRequestMethod("POST"); conn.setRequestProperty("Connection", "Keep-Alive"); conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); DataOutputStream dos = new DataOutputStream(conn.getOutputStream()); dos.writeBytes(twoHyphens + boundary + lineEnd); dos .writeBytes("Content-Disposition: post-data; name=uploadedfile;filename=" + exsistingFileName + "" + lineEnd); dos.writeBytes(lineEnd); Log.e(Tag, "Headers are written"); // create a buffer of maximum size int bytesAvailable = fileInputStream.available(); int maxBufferSize = 1000; // int bufferSize = Math.min(bytesAvailable, maxBufferSize); byte[] buffer = new byte[bytesAvailable]; // read file and write it into form... int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable); while (bytesRead > 0) { dos.write(buffer, 0, bytesAvailable); bytesAvailable = fileInputStream.available(); bytesAvailable = Math.min(bytesAvailable, maxBufferSize); bytesRead = fileInputStream.read(buffer, 0, bytesAvailable); } // send multipart form data necessary after file data... dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); // close streams Log.e(Tag, "File is written"); fileInputStream.close(); dos.flush(); dos.close(); } catch (MalformedURLException ex) { Log.e(Tag, "error: " + ex.getMessage(), ex); } catch (IOException ioe) { Log.e(Tag, "error: " + ioe.getMessage(), ioe); } try { BufferedReader rd = new BufferedReader(new InputStreamReader(conn .getInputStream())); String line; while ((line = rd.readLine()) != null) { Log.e("Dialoge Box", "Message: " + line); } rd.close(); } catch (IOException ioex) { Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex); } } 我是服务器编程的新手。 如果我犯了任何错误，请澄清我。 谢谢！
实现这一目标的最佳库仍然是Apache Commons File Upload 。 它文档齐全，易于使用。 如果您遇到任何问题，请先查看常见问题解答 。