调用soap webservice从带有轴的java客户端返回对象列表

我对webservices感到生气。

我有一个非常简单的soap webservice：

@Remote public interface StudentService { public String sayHello(); public List getStudents(); } 

和

 @Stateless @WebService public class StudentServiceImpl implements StudentService { @Override public String sayHello() { return "Hello World"; } public List getStudents() { List students = new ArrayList(); Student st1 = new Student(); st1.setMatricule(1234); st1.setName("student1"); students.add(st1); Student st2 = new Student(); st2.setMatricule(5678); st2.setName("student2"); students.add(st2); return students; } } 

和

 public class Student implements Serializable { private static final long serialVersionUID = 8286393242028201686L; private int matricule; private String name; public int getMatricule() { return matricule; } public void setMatricule(int matricule) { this.matricule = matricule; } public String getName() { return name; } public void setName(String name) { this.name = name; } } 

我在glassfish 3.1下部署服务。

使用glassfish控制台，它正在工作。

      1234 student1   5678 student2     

使用php它也可以工作（对于这两种方法）。

现在有了一个java客户端：

 import javax.xml.namespace.QName; import org.apache.axis.client.Call; import org.apache.axis.client.Service; public class Client { public static void main(String[] args) throws Exception { String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl"; Service service = new Service(); Call call = (Call) service.createCall(); call.setTargetEndpointAddress(new java.net.URL(endPoint)); call.setOperationName(new QName("http://services.tuto.java.com/","sayHello")); System.out.println(call.invoke(new Object[0])); Service service2 = new Service(); Call call2 = (Call) service2.createCall(); call2.setTargetEndpointAddress(new java.net.URL(endPoint)); call2.setOperationName(new QName("http://services.tuto.java.com/","getStudents")); System.out.println(call2.invoke(new Object[0])); } } 

第一个电话正在工作但不是第二个电话。

 Hello World 12-mars-2012 14:53:23 org.apache.axis.client.Call invoke GRAVE: Exception: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize. at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145) at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035) at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165) at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141) at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345) at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384) at org.apache.axis.client.Call.invoke(Call.java:2467) at org.apache.axis.client.Call.invoke(Call.java:2366) at org.apache.axis.client.Call.invoke(Call.java:1812) at Client.main(Client.java:24) 

我能做什么 ？

经过大量的时间在网上搜索并尝试不同的解决方案仍然没有任何工作…

有简单的解决方案吗？

谢谢。

编辑：

还试过：

 public class SoapClient { public static void main(String[] args) throws Exception { SOAPMappingRegistry smr = new SOAPMappingRegistry(); BeanSerializer beanSer = new BeanSerializer(); smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("http://services.tuto.java.com/", "StudentServiceImplService"),Student.class, beanSer, beanSer); Call call = new Call(); call.setSOAPMappingRegistry(smr); call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC); call.setTargetObjectURI("http://services.tuto.java.com/"); call.setMethodName("getStudents"); Response resp; try { resp = call.invoke(new URL("http://8h9l45j:8080/StudentServiceImplService/StudentServiceImpl"), ""); } catch (SOAPException e) { System.err.println("Caught SOAPException (" + e.getFaultCode() + "): " + e.getMessage()); return; } if (!resp.generatedFault()) { Parameter ret = resp.getReturnValue(); Object value = ret.getValue(); if ( value != null ) { String[] tlist = (String[])value; System.out.println(); for ( int i = 0; i < tlist.length; i++ ) System.out.println(tlist[i]); } } else { Fault fault = resp.getFault(); System.err.println("Generated fault: "); System.out.println (" Fault Code = " + fault.getFaultCode()); System.out.println (" Fault String = " + fault.getFaultString()); } } 

结果如下：

 Caught SOAPException (SOAP-ENV:Client): No Deserializer found to deserialize a ':return' using encoding style 'http://schemas.xmlsoap.org/soap/encoding/'. 

Answer 1

使用soap客户端的第一个响应元素。

问题来自maptypes名称空间：没有名称空间

所以现在，我有

  smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","student"),Student.class, null, new BeanSerializer()); smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","matricule"),Integer.class, null, new IntDeserializer()); smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","name"),Integer.class, null, new StringDeserializer()); 

并补充说

 @XmlRootElement(name = "Student",namespace="http://services.tuto.java.com/") 

到学生class来

      1236 student1   5678 student2     

轴客户端：

  public class AxisClient { public static void main(String[] args) throws Exception { String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl"; Service service2 = new Service(); Call call2 = (Call) service2.createCall(); call2.setTargetEndpointAddress(new java.net.URL(endPoint)); call2.setOperationName(new QName("http://services.tuto.java.com/","getStudents")); call2.setReturnType(new QName("","student"), Student.class); call2.setReturnType(new QName("", "student")); call2.registerTypeMapping(Student.class, new QName("", "student"), null,new BeanDeserializerFactory(Student.class, new QName("", "student"))); List students = (List) call2.invoke(new Object[0]); for (Student student : students) { System.out.println(student); } } } 

给所有学生：

 Student [matricule=1236, name=student1] Student [matricule=5678, name=student2] 

axis2客户端：

 public static void main(String[] args) throws Exception { String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl"; ServiceClient sc = new ServiceClient(); Options opts = new Options(); opts.setTo(new EndpointReference("http://localhost:8080/StudentServiceImplService/StudentServiceImpl")); sc.setOptions(opts); OMFactory fac = OMAbstractFactory.getOMFactory(); OMNamespace omNs = fac.createOMNamespace("http://services.tuto.java.com/","ns1"); OMElement method = fac.createOMElement("getStudents", omNs); OMElement res = sc.sendReceive(method); System.out.println(res); Iterator it = res.getChildElements(); while(it.hasNext()) { System.out.println(it.next()); } } 

给予

 1236student15678student2 1236student1 5678student2 

但我不知道如何反序列化这些元素。

我试过了

 Student student = (Student) BeanUtil.deserialize(Student.class,res,new DefaultObjectSupplier(),null); 

但是给了我

 Student [matricule=null, name=null] 

我能怎么做 ？

留下问题：

• 不知道如何对轴做同样的事–OK见之前 – /轴2
• ‘resp’（肥皂客户端） 只包含第一个学生

Answer 2

你能不能像WSDL那样得到它

 http://localhost:8080/StudentServiceImplService/StudentServiceImpl?wsdl 

然后使用axis wsdl2java让Axis为你创建客户端代码（它将具有所有正确的类型映射和命名空间）？

Answer 3

什么是你正在使用的SOAP绑定样式， RPC / DOCUMENT ？ 如果您使用RPC，则将对请求和响应进行编码和处理，Axis2不支持RPC编码格式消息。 尝试使用DOCUMENT SOAP绑定样式。 （我应该把它放在评论中，请耐心等待）

请参阅https://stackoverflow.com/a/9598193/752129