为任何整数输入参数设置模拟返回值
when(candidateService.findById(1)).thenReturn(new Candidate());
我想为任何整数扩展此行为(不一定是1)
如果我啰嗦
when(candidateService.findById( any(Integer.class) )).thenReturn(new Candidate());
我有编译错误
CandidateService类型中的方法findById(Integer)不适用于参数(Matcher)
UPDATE
import:
import static org.junit.Assert.assertEquals; import static org.mockito.Matchers.anyInt; import static org.mockito.Matchers.anyString; import static org.mockito.Mockito.mock; import static org.mockito.Mockito.times; import static org.mockito.Mockito.verify; import static org.mockito.Mockito.when; import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status; import java.util.ArrayList; import java.util.HashSet; import org.junit.Before; import org.junit.Test; import org.junit.runner.RunWith; import org.mockito.InjectMocks; import org.mockito.Mock; import org.mockito.MockitoAnnotations;
尝试anyInt():
when(candidateService.findById( anyInt())).thenReturn(new Candidate());
例如,我的项目中有anyLong():
when(dao.getAddress(anyLong())).thenReturn(Arrays.asList(dto));
编辑:您必须导入:
import static org.mockito.Matchers.anyInt;