编写一个从用户输入三个整数的应用程序，并显示数字的总和，平均值，乘积，最小值和最大值

我得到了总和，平均值和产品。 我面临的真正困难是最小和最大的数字。

我可以用两个数字来做，但是三个数字对我没有任何意义。 问我，我的问题是不清楚，还是没有意义。

import java.util.Scanner; // exercise 2.17 public class ArithmeticSmallestLargest { public static void main(String[] args) { Scanner input = new Scanner(System.in); int num1; int num2; int num3; int sum; int average; int product; double largest System.out.print("Enter First Integer: "); num1 = input.nextInt(); System.out.print("Enter Second Integer: "); num2 = input.nextInt(); System.out.print("Enter Third Integer: "); num3 = input.nextInt(); sum = num1 + num2 + num3; average = sum / 3; product = num1 * num2 * num3; if (largest =num1 > num2 & num2 > num3) System.out.println(sum); System.out.println(average); System.out.println(product); System.out.println("The biggest number is " + largest); } } 

Answer 1

 import java.util.Scanner; // exercise 2.17 public class ArithmeticSmallestLargest { public static void main(String[] args) { Scanner input = new Scanner(System.in); int num1; int num2; int num3; int sum; int average; int product; int largest; int smallest; System.out.print("Enter First Integer: "); num1 = input.nextInt(); System.out.print("Enter Second Integer: "); num2 = input.nextInt(); System.out.print("Enter Third Integer: "); num3 = input.nextInt(); sum = num1 + num2 + num3; average = sum / 3; product = num1 * num2 * num3; largest = num1; smallest = num1; if(num2 > largest) largest = num2; if(num3 > largest) largest = num3; if(num2 < smallest) smallest = num2; if (num3 < smallest) smallest = num3; System.out.println("The sum is " + sum); System.out.println("The average is " + average); System.out.println("The product is " + product); System.out.println("Largest of three integers is " + largest + " and the smallest is "+ smallest + "."); } } 

Answer 2

 import java.util.Scanner; public class ArithmeticSmallestLargest { public static void main(String[] args) { Scanner input = new Scanner(System.in); int num1; int num2; int num3; int sum; int average; int product; int largest; int smallest; System.out.print("Enter First Integer: "); num1 = input.nextInt(); System.out.print("Enter Second Integer: "); num2 = input.nextInt(); System.out.print("Enter Third Integer: "); num3 = input.nextInt(); sum = num1 + num2 + num3; average = sum / 3; product = num1 * num2 * num3; largest = num1; smallest = num1; if(num2 > largest) largest = num2; if(num3 > largest) largest = num3; if(num2 < smallest) smallest = num2; if (num3 < smallest) smallest = num3; System.out.printf("The sum is %d%n " , sum); System.out.printf("The average is %d%n " , average); System.out.printf("The product is %d%n " , product); System.out.printf("Largest of three integers is %d%n " , largest); System.out.printf("Smallest of three integers is %d%n " , smallest); } } 

答案如下：

输入第一个整​​数：60
输入第二个整数：90
输入第三个整数：30

总和是180
平均是60
该产品是162000
三个整数中最大的是90
三个整数中最小的是30

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