如何转换int以便返回字符串,这就是我们说int的方式

我遇到了这个面试问题,面试官要求编写一个函数,它将取一个整数,比如说123,并返回一个字符串,就像人们会说整数一样。在上面的例子中,输出应该是“一百二十三” “。我不知道如何解决这些问题。任何人都可以帮忙解决这个问题吗? 伪代码将是有用的。

在此处使用此代码将数字转换为Word Source

public class YourNumberMyWord { public void pw(int n,String ch) { String one[]={" "," one"," two"," three"," four"," five"," " + "six"," seven"," eight"," Nine"," ten"," eleven"," twelve"," " + "thirteen"," fourteen","fifteen"," sixteen"," seventeen"," eighteen"," nineteen"}; String ten[]={" "," "," twenty"," thirty"," forty"," fifty"," sixty","seventy"," eighty"," ninety"}; if(n>19) { System.out.print(ten[n/10]+" "+one[n%10]); } else { System.out.print(one[n]);} if(n>0)System.out.print(ch); } public static void main(String[] args) { int n=0; Scanner scanf = new Scanner(System.in); System.out.println("Enter an integer number: "); n = scanf.nextInt(); if(n<=0) System.out.println("Enter numbers greater than 0"); else { YourNumberMyWord a = new YourNumberMyWord(); a.pw((n/1000000000)," Hundred"); a.pw((n/10000000)%100," crore"); a.pw(((n/100000)%100)," lakh"); a.pw(((n/1000)%100)," thousand"); a.pw(((n/100)%10)," hundred"); a.pw((n%100)," "); } } } 

以下是您的问题的解决方案:

数字到单词

它并不像你想象的那么简单。

使用前面编写的相同convertLessThanOneThousand函数。

 private static String pronounce(int number) { String result = ""; int cnt = 0; while (number != 0) { int rem = number % 1000; result = convertLessThanOneThousand(rem) + result; number = number / 1000; cnt++; if (number != 0) { switch (cnt) { case 1: result = " thousand " + result; break; case 2: result = " million " + result; break; case 3: result = " billion " + result; break; } } } return result; } 

这是我将int转换为英文单词的代码。 希望能帮助到你。

 public class Excercise1 { static String words[]={"One","Two","Three","Four","Five", "Six", "Seven", "Eight", "Nine", "Ten"}; public static void main(String[] args){ String inputValue = JOptionPane.showInputDialog("Please input a value"); int num = Integer.parseInt(inputValue.toString()); if(num <= 10){ System.out.println(words[num-1]); } else { JOptionPane.showMessageDialog(null, "You must put number 1 - 10", "alert", JOptionPane.ERROR_MESSAGE); } } } 

现在有很多方法

1.String.valueOf(intVarable)

2.Integer.toString(intVarable)

 public class ConvertIntToString { public static void main(String[] args) { int aInt = 1; String aString = Integer.toString(aInt); } }