java中json文档中叶节点的所有路径的输出列表

例如：给出这个json文档：

{ "store": { "book": [ { "category": "reference", "author": "Nigel Rees", "title": "Sayings of the Century", "price": 8.95 }, { "category": "fiction", "author": "Herman Melville", "title": "Moby Dick", "isbn": "0-553-21311-3", "price": 8.99 }, ], "bicycle": { "color": "red", "price": 19.95 } }, "expensive": 10 } 

我想生产（类似）这个输出：

 store.book.category: "reference" store.book.author: "Nigel Rees" store.book.title: "Sayings of the Century" store.book.price: 8.95 store.book.category: "fiction" store.book.author: "Herman Melville" store.book.title: "Moby Dick" store.book.isbn: "0-553-21311-3" store.book.price: 8.99 store.bicycle.color: "red" store.bicycle.price: 19.95 expensive:10 

我宁愿选择一个基于强大的json库（gson，jackson等）之一的有效解决方案，而不是使用原始文本。

Answer 1

以下是org.json的示例代码。 但是同样可以与Gson / Jackson一起使用，改变这些库中的适当类型。 你也可以在这里使用StringBuilder而不是String作为键。

 import java.util.Iterator; import org.json.JSONArray; import org.json.JSONObject; public class MyJSONTest { private static void listJson(JSONObject json) { listJSONObject("", json); } private static void listObject(String parent, Object data) { if (data instanceof JSONObject) { listJSONObject(parent, (JSONObject)data); } else if (data instanceof JSONArray) { listJSONArray(parent, (JSONArray) data); } else { listPrimitive(parent, data); } } private static void listJSONObject(String parent, JSONObject json) { Iterator it = json.keys(); while (it.hasNext()) { String key = (String)it.next(); Object child = json.get(key); String childKey = parent.isEmpty() ? key : parent + "." + key; listObject(childKey, child); } } private static void listJSONArray(String parent, JSONArray json) { for (int i = 0; i < json.length(); i++) { Object data = json.get(i); listObject(parent + "[" + i + "]", data); } } private static void listPrimitive(String parent, Object obj) { System.out.println(parent + ":" + obj); } public static void main(String[] args) { String data = "{\"store\":{\"book\":[{\"category\":\"reference\",\"author\":\"NigelRees\",\"title\":\"SayingsoftheCentury\",\"price\":8.95},{\"category\":\"fiction\",\"author\":\"HermanMelville\",\"title\":\"MobyDick\",\"isbn\":\"0-553-21311-3\",\"price\":8.99},],\"bicycle\":{\"color\":\"red\",\"price\":19.95}},\"expensive\":10}"; JSONObject json = new JSONObject(data); System.out.println(json.toString(2)); listJson(json); } } 

Answer 2

事实certificate，使用Gson非常容易，尤其是2.3中引入的JsonReader.getPath（）方法。

 static void parseJson(String json) throws IOException { JsonReader reader = new JsonReader(new StringReader(json)); reader.setLenient(true); while (true) { JsonToken token = reader.peek(); switch (token) { case BEGIN_ARRAY: reader.beginArray(); break; case END_ARRAY: reader.endArray(); break; case BEGIN_OBJECT: reader.beginObject(); break; case END_OBJECT: reader.endObject(); break; case NAME: reader.nextName(); break; case STRING: String s = reader.nextString(); print(reader.getPath(), quote(s)); break; case NUMBER: String n = reader.nextString(); print(reader.getPath(), n); break; case BOOLEAN: boolean b = reader.nextBoolean(); print(reader.getPath(), b); break; case NULL: reader.nextNull(); break; case END_DOCUMENT: return; } } } static private void print(String path, Object value) { path = path.substring(2); path = PATTERN.matcher(path).replaceAll(""); System.out.println(path + ": " + value); } static private String quote(String s) { return new StringBuilder() .append('"') .append(s) .append('"') .toString(); } static final String REGEX = "\\[[0-9]+\\]"; static final Pattern PATTERN = Pattern.compile(REGEX);