JAXB，Marshal的问题， – 无法编组类型“java.lang.String”
当我运行marshal操作时，我收到以下错误：
javax.xml.bind.MarshalException - with linked exception: [com.sun.istack.internal.SAXException2: unable to marshal type "java.lang.String" as an element because it is missing an @XmlRootElement annotation] ... Caused by: com.sun.istack.internal.SAXException2: unable to marshal type "java.lang.String" as an element because it is missing an @XmlRootElement annotation at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.reportError(XMLSerializer.java:237) at com.sun.xml.internal.bind.v2.runtime.LeafBeanInfoImpl.serializeRoot(LeafBeanInfoImpl.java:126) at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.childAsRoot(XMLSerializer.java:483) at com.sun.xml.internal.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:308) ... 6 more 这是我编组的function……
public StringBuffer Marshaller(Object marshall){ // make marshalling->Java to XML StringWriter writer = new StringWriter(); try { JAXBContext jaxbContext=JAXBContext.newInstance(marshall.getClass()); Marshaller jaxbMarshaller=jaxbContext.createMarshaller(); // çıktı jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); jaxbMarshaller.marshal(marshall, writer); System.out.println(writer.getBuffer().toString()); } catch (PropertyException e) { e.printStackTrace(); } catch (JAXBException e) { e.printStackTrace(); } return writer.getBuffer(); }
谢谢你的兴趣..
你不能只编组一个String因为它没有任何根元素信息（因此关于缺少的@XmlRootElement注释的例外），但是你可以将它包装在JAXBElement一个实例中然后编组它。 JAXBElement是向JAXB提供此根元素信息的另一种方法。
创建JAXBElement示例
JAXBElement jaxbElement = new JAXBElement(new QName("root-element"), String.class, string);
如果您从XML架构生成模型
如果您是从XML架构创建对象模型。 并且您有一个顶级XML元素，它是一个像xs:string这样的数据类型，然后在生成的ObjectFactory类上会有一个方便的方法来帮助您创建JAXBElement实例。