从Java中删除字符串中的特定字符

例如，给定一串Battle of the Vowels:Hawaii vs Gronzy当我们指定要删除的字符为aeiou ，该函数应该将字符串转换为Bttl f th V wls:Hw vs Grzny 。

在Programming Interviews Exposed一书中找到了这个问题。 这在C中有解释，但我对Java很感兴趣。

Answer 1

一种简单的方法是使用正则表达式：

 "Battle of the Vowels:Hawaii vs Gronzy".replaceAll("[aeiou]","") 

一些Java类库API文档：

String.replaceAll： http ： //download.oracle.com/javase/1.5.0/docs/api/java/lang/String.html#replaceAll( java.lang.String,%20java.lang.String ）

模式和正则表达式： http ： //download.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html#sum

Answer 2

 public class RemoveChars { char[] replaceChar = {'a','e','i','o','u'}; public static void main(String[] args) { String src = "Battle of the Vowels:Hawaii vs Gronzy"; System.out.println(new RemoveChars().removeChar(src)); } public String removeChar(String src){ char[] srcArr = src.toCharArray(); StringBuilder sb = new StringBuilder(); for (int i = 0; i < srcArr.length; i++) { char foundChar = isFound(srcArr[i]); if(foundChar!='\0') sb.append(foundChar); } return sb.toString(); } public char isFound(char src){ for (int i = 0; i < replaceChar.length; i++) { if(src==replaceChar[i]){ return '\0'; } } return src; } } 

Answer 3

 public class RemoveCharacters { static String removeCharsFromString(String word1, String word2) { StringBuilder sb = new StringBuilder(word1); System.out.println(sb); //char[] word2characters= word2.toCharArray(); HashMap table = new HashMap(); for (int i = 0; i < word2.length(); i++) { table.put(word2.charAt(i), 1); } int p = 0; for (int i = 0; i < word1.length(); i++) { if (table.containsKey(word1.charAt(i))) { if (p == 0) { sb.deleteCharAt(i); //p++; } else { sb.deleteCharAt(i - p); } //System.out.println(sb); p++; } } return sb.toString(); } public static void main(String[] args) { System.out.println("Enter your string"); Scanner sc = new Scanner(System.in); String originalword = sc.nextLine(); System.out.println("Enter the remove string"); Scanner sc1 = new Scanner(System.in); String removecharacters = sc1.nextLine(); String result = removeCharsFromString(originalword, removecharacters); System.out.println(result); } }