无法加密特殊字符：不是块长度的倍数

我有一个加密/解密算法，我正在尝试加密一些特殊字符从android发送到服务器，但它抛出exception：

java.lang.Exception：[encrypt]错误：0607F08A：数字包络例程：EVP_EncryptFinal_ex：数据不是块长度的倍数

普通拉丁字符加密/解密正常，但特殊字符不是。

这是我的代码：

public class MCrypt { private String iv = "fedcba9876543210";//Dummy iv (CHANGE IT!) private IvParameterSpec ivspec; private SecretKeySpec keyspec; private Cipher cipher; private String SecretKey = "0123456789abcdef";//Dummy secretKey (CHANGE IT!) public MCrypt() { ivspec = new IvParameterSpec(iv.getBytes()); keyspec = new SecretKeySpec(SecretKey.getBytes(), "AES"); try { cipher = Cipher.getInstance("AES/CBC/NoPadding"); } catch (NoSuchAlgorithmException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (NoSuchPaddingException e) { // TODO Auto-generated catch block e.printStackTrace(); } } public byte[] encrypt(String text) throws Exception { //if(text == null || text.length() == 0) // throw new Exception("Empty string"); byte[] encrypted = null; try { cipher.init(Cipher.ENCRYPT_MODE, keyspec, ivspec); encrypted = cipher.doFinal(padString(text).getBytes()); } catch (Exception e) { throw new Exception("[encrypt] " + e.getMessage()); } return encrypted; } public byte[] decrypt(String code) throws Exception { if(code == null || code.length() == 0) throw new Exception("Empty string"); byte[] decrypted = null; try { cipher.init(Cipher.DECRYPT_MODE, keyspec, ivspec); decrypted = cipher.doFinal(hexToBytes(code)); } catch (Exception e) { throw new Exception("[decrypt] " + e.getMessage()); } return decrypted; } public static String bytesToHex(byte[] data) { if (data==null) { return null; } int len = data.length; String str = ""; for (int i=0; i<len; i++) { if ((data[i]&0xFF)<16) str = str + "0" + Integer.toHexString(data[i]&0xFF); else str = str + Integer.toHexString(data[i]&0xFF); } return str; } public static byte[] hexToBytes(String str) { if (str==null) { return null; } else if (str.length() < 2) { return null; } else { int len = str.length() / 2; byte[] buffer = new byte[len]; for (int i=0; i<len; i++) { buffer[i] = (byte) Integer.parseInt(str.substring(i*2,i*2+2),16); } return buffer; } } private static String padString(String source) { char paddingChar = ' '; int size = 32; int x = source.length() % size; int padLength = size - x; for (int i = 0; i < padLength; i++) { source += paddingChar; } return source; } } 

有谁知道这里的问题是什么？

谢谢！

Answer 1

改变这一行：

 cipher = Cipher.getInstance("AES/CBC/NoPadding"); 

至

 cipher = Cipher.getInstance("AES/CBC/PKCS5Padding"); 

Answer 2

来自这个博客

改变这一行：

 cipher = Cipher.getInstance("AES/CBC/NoPadding"); //this may be not decrypt full plaintext. 

至：

 cipher = Cipher.getInstance("AES/ECB/PKCS7Padding"); // use this for descrypt full plain text without lost.