将XML转换为Java Map
我正在尝试将XML转换为Java代码。 此XML位于不同的文件中; 它匹配单词与数字（概率分布），看起来像这样：
1 2 2 3 2 1 5 1 1 22 2 26 ....... 我正在尝试将其转换为Java Map，这是我正在使用的代码：
XStream xstream = new XStream(); @SuppressWarnings("unchecked") Map englishCorpusProbDist = (Map)xstream.fromXML(new File("LocationOfFileOnMyComputer/frequencies.xml"));
目前，每当我尝试运行上述Java代码时，我在控制台中都会遇到以下exception：
Exception in thread "main" com.thoughtworks.xstream.mapper.CannotResolveClassException: root at com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:79) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.DynamicProxyMapper.realClass(DynamicProxyMapper.java:55) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.PackageAliasingMapper.realClass(PackageAliasingMapper.java:88) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.ClassAliasingMapper.realClass(ClassAliasingMapper.java:79) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.ArrayMapper.realClass(ArrayMapper.java:74) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.SecurityMapper.realClass(SecurityMapper.java:71) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.CachingMapper.realClass(CachingMapper.java:47) at com.thoughtworks.xstream.core.util.HierarchicalStreams.readClassType(HierarchicalStreams.java:29) at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:133) at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32) at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1185) at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1169) at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1133) at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1075) at ProductAttributeExtractor.main(ProductAttributeExtractor.java:23)
这是一个相关的post，但我的问题是增加了一层复杂性，因为我的XML匹配带有整数的字符串，不幸的是Java Map不能使用整数，它必须使用整数（这是非常令人沮丧的）： 如何将XML转换为java.util.Map，反之亦然
任何帮助你都会非常感激。 提前致谢！
您需要注册MapConverter，这是实现Converter的类
xstream.registerConverter（new MapEntryConverter（））;
希望有所帮助
Underscore-java库可以将xml转换为hashmap，反之亦然。 我是该项目的维护者。 实例
代码示例：
import com.github.underscore.lodash.U; public class Main { public static void main(String[] args) { String xml = "" + "" + " 1 " + " 2 " + " 2 " + " 3 " + " 2 " + " 1 " + " 5 " + " 1 " + " 1 " + " 22 " + " 2 " + " 26 " + " "; String result = U.fromXml(xml).toString(); // "{Durapipe=1, EXPLAIN=2, woods=2, hanging=3, hastily=2, localized=1, " // "Schuster=5, regularize=1, LASR=1, LAST=22, Gelch=2, Gelco=26}" } }