如何在Java中进行交替转弯

好的，所以我在AP计算机科学的9年级，我们得到了一个制作游戏的项目。 我选了一个我老师建议的简单的Game of Chi游戏。 但我无法弄清楚的是如何在计算机和播放器之间进行交替转弯。

import java.util.Scanner; /** * Game of Chi .. see main for gameplay * * @author ..... */ public class GameOfChi { private static int numStonesLeft = 0; public static void main(String[] args) { numStonesLeft = (int) (Math.random() * 16) + 15;// btw 15 & 30 stones System.out.println("This is the Game of Chi."); System.out.println("There is a pile of " + numStonesLeft + " stones between us."); System.out.println("We alternate taking either 1,2 or 3 stones."); System.out.println("The person who takes the last stone loses"); // Write a loop to alternate computerTurn() and playerTurn() // checking after each turn see if there is a winner to print // and to break the loop ... then output the winner computerTurn(); // invoke the computerTurn() method playerTurn(); // invoke the playerTurn() method while (numStonesLeft> 0); } /** * The computerTurn method chooses a random number from 1 to 3 if * numStonesLeft is greater than or equal to 3, otherwise chooses a random * number from 1 to numStonesLeft. * * Then decrements numStonesLeft appropriately and prints the turn. */ public static void computerTurn() { int stonesChosen = 1 + (int) (Math.random() * Math .min(3, numStonesLeft)); numStonesLeft -= stonesChosen; System.out.println("\nI took " + stonesChosen + " stones."); System.out.println("There are " + numStonesLeft + " stones left."); } /** * The playerTurn method prompts the user for a valid number of stones to * choose and reads an int value from the user and will repeat this action * while the user input is invalid. (ie user must choose 1, 2 or 3 AND * their choice must be less than or equal to numStonesLeft.) * * Also decrements numStonesLeft appropriately and prints the turn. */ public static void playerTurn() { Scanner keyboard = new Scanner(System.in); System.out.println("Number of stones you take this turn:"); int stonesChosen = 0; stonesChosen = keyboard.nextInt(); while (stonesChosen > 3 || stonesChosen < 1) { ; System.out.println("That is an invalid number of stones."); stonesChosen = keyboard.nextInt(); } if (stonesChosen = 1) ; { System.out.println("\nYou took " + stonesChosen + " stones."); System.out.println("There are " + (numStonesLeft - stonesChosen) + " stones left."); } stonesChosen = keyboard.nextInt(); } } 

Answer 1

在你的main方法中创建一些while循环来检查游戏是否结束。

 while(!gameEnded) { playerTurn(); computerTurn(); } 

除非你问如何使计算机首先播放然后下一轮播放器首先播放。 在这种情况下，添加一个计数器来跟踪最后一个人。

 while(!gameEnded) { if(counter%2 = 0) { playerTurn(); computerTurn(); } if(counter%2 = 1) { computerTurn(); playerTurn(); } couter++; } 

要随机选择第一个转发的玩家，您可以使用奇数或偶数初始化计数器。

 int counter = Math.random()*2; 

Answer 2

 do { // // Other code from above as required. // ... // computerTurn(); // invoke the computerTurn() method // // Can numStonesLeft be 0 after the computer turn? // If so, perhaps you need an extra check... // playerTurn(); // invoke the playerTurn() method } while (numStonesLeft> 0);