使用@OneToMany Map的EclipseLink JPA“此上下文中的无效表”
我希望我在这里做些傻事……
我正在尝试为Map设置JPA注释并获得以下堆栈跟踪。
Exception [EclipseLink-6069] (Eclipse Persistence Services - 2.4.1.v20121003-ad44345): org.eclipse.persistence.exceptions.QueryException Exception Description: The field [EMPLOYEE.PHONE_TYPE] in this expression has an invalid table in this context. Query: ReadAllQuery(name="phones" referenceClass=Phone ) at org.eclipse.persistence.exceptions.QueryException.invalidTableForFieldInExpression(QueryException.java:739) at org.eclipse.persistence.internal.expressions.FieldExpression.validateNode(FieldExpression.java:281) at org.eclipse.persistence.expressions.Expression.normalize(Expression.java:3259) at org.eclipse.persistence.internal.expressions.DataExpression.normalize(DataExpression.java:369) at org.eclipse.persistence.internal.expressions.FieldExpression.normalize(FieldExpression.java:208) at org.eclipse.persistence.internal.expressions.SQLSelectStatement.normalize(SQLSelectStatement.java:1377) at org.eclipse.persistence.internal.queries.ExpressionQueryMechanism.buildNormalSelectStatement(ExpressionQueryMechanism.java:546) at org.eclipse.persistence.internal.queries.ExpressionQueryMechanism.prepareSelectAllRows(ExpressionQueryMechanism.java:1700) at org.eclipse.persistence.queries.ReadAllQuery.prepareSelectAllRows(ReadAllQuery.java:721) at org.eclipse.persistence.queries.ReadAllQuery.prepare(ReadAllQuery.java:657) at org.eclipse.persistence.queries.DatabaseQuery.checkPrepare(DatabaseQuery.java:614) at org.eclipse.persistence.queries.ObjectLevelReadQuery.checkPrepare(ObjectLevelReadQuery.java:883) at org.eclipse.persistence.queries.DatabaseQuery.checkPrepare(DatabaseQuery.java:575) at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:820) at org.eclipse.persistence.queries.ObjectLevelReadQuery.execute(ObjectLevelReadQuery.java:1109) at org.eclipse.persistence.queries.ReadAllQuery.execute(ReadAllQuery.java:393) at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeInUnitOfWork(ObjectLevelReadQuery.java:1197) at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2875) at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1602) at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1584) at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.instantiate(QueryBasedValueHolder.java:112) at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.instantiate(QueryBasedValueHolder.java:99) at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getValue(DatabaseValueHolder.java:88) at org.eclipse.persistence.internal.indirection.UnitOfWorkValueHolder.instantiateImpl(UnitOfWorkValueHolder.java:161) at org.eclipse.persistence.internal.indirection.UnitOfWorkValueHolder.instantiate(UnitOfWorkValueHolder.java:222) at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getValue(DatabaseValueHolder.java:88) at org.eclipse.persistence.indirection.IndirectMap.buildDelegate(IndirectMap.java:110) at org.eclipse.persistence.indirection.IndirectMap.getDelegate(IndirectMap.java:330) at org.eclipse.persistence.indirection.IndirectMap.size(IndirectMap.java:637) at org.eclipse.persistence.internal.queries.MapContainerPolicy.sizeFor(MapContainerPolicy.java:830) at org.eclipse.persistence.internal.indirection.TransparentIndirectionPolicy.instantiateObject(TransparentIndirectionPolicy.java:386) at org.eclipse.persistence.mappings.ForeignReferenceMapping.buildCloneFromRow(ForeignReferenceMapping.java:285) at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildAttributesIntoWorkingCopyClone(ObjectBuilder.java:1594) at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildWorkingCopyCloneFromRow(ObjectBuilder.java:1741) at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObjectInUnitOfWork(ObjectBuilder.java:668) at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObject(ObjectBuilder.java:605) at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObject(ObjectBuilder.java:564) at org.eclipse.persistence.queries.ObjectLevelReadQuery.buildObject(ObjectLevelReadQuery.java:777) at org.eclipse.persistence.queries.ReadAllQuery.registerResultInUnitOfWork(ReadAllQuery.java:783) at org.eclipse.persistence.queries.ReadAllQuery.executeObjectLevelReadQuery(ReadAllQuery.java:434) at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeDatabaseQuery(ObjectLevelReadQuery.java:1150) at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:852) at org.eclipse.persistence.queries.ObjectLevelReadQuery.execute(ObjectLevelReadQuery.java:1109) at org.eclipse.persistence.queries.ReadAllQuery.execute(ReadAllQuery.java:393) at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeInUnitOfWork(ObjectLevelReadQuery.java:1197) at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2875) at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1602) at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1584) at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1549) at org.eclipse.persistence.internal.jpa.QueryImpl.executeReadQuery(QueryImpl.java:231) at org.eclipse.persistence.internal.jpa.QueryImpl.getResultList(QueryImpl.java:411) at aaa.Test.main(Test.java:20)
创建的表格如下所示：
EMP_PHONE ================================= EMP_ID PHONES_ID PHONE_TYPE ------ --------- ---------- 42 1 NULL EMPLOYEE ================================= ID -- 42 PHONE ================================= ID NUM -- -------- 1 867-5309
NULL PHONE_TYPE似乎告诉我一些时髦的事情，以及PHONE_TYPE寻找EMPLOYEE.PHONE_TYPE让我觉得它正在考虑来自PHONE – > EMPLOYEE的关系，而不是相反。
JPA实体定义如下。 电话映射是单向的，Phone对象应由多个Employees共享（不是我的实际类型，但这个简化示例演示了这个问题）
@Entity public class Employee { @Id private long id; @OneToMany(cascade=CascadeType.ALL) @JoinTable(name="EMP_PHONE", joinColumns=@JoinColumn(name="EMP_ID")) @MapKeyColumn(name="PHONE_TYPE") private Map phones = new HashMap(); public Employee() {} public Employee(long id) { this.id = id; } public long getId() { return id; } public Map getPhones() { return phones; } } @Entity public class Phone { @Id private long id; private String num; public String getNum() { return num; } public Phone() {} public Phone(String num) { this.num = num; } public Phone(long id, String num) { this.id = id; this.num = num; } public long getId() { return id; } }
使用以下测试代码
EntityManagerFactory factory = Persistence.createEntityManagerFactory("test"); EntityManager em = factory.createEntityManager(); Employee employee = new Employee(42); // exception will occur with or without phones added to the map employee.getPhones().put("home", new Phone(1, "867-5309")); em.getTransaction().begin(); em.persist(employee); em.getTransaction().commit(); Query q = em.createQuery("select o from Employee o"); q.setHint("javax.persistence.cache.storeMode", "REFRESH"); q.getResultList(); // EXCEPTION THROWN HERE
和persistence.xml：
org.eclipse.persistence.jpa.PersistenceProvider aaa.Phone aaa.Employee NONE
我在Windows 7上运行，使用Oracle XE 11g作为数据库。 提前感谢您的任何见解！
这看起来像EclipseLink错误364922 ：
具有单向OneToMany属性和@MapKeyColumn批注的实体创建了正确的数据库表，映射表包含“键列，但持久化实体仅填充id列而不是键列。持久化操作不会抛出错误，但后续查询很快失败，并显示以下错误：exception说明：此表达式中的字段[ORGANIZATION.MAILINGADDRESSES_KEY]在此上下文中具有无效表。
为了它的价值，我使用Hibernate / H2测试了你的代码，它运行正常。
UPDATE
我刚用EclipseLink测试了这个。 如果为MapKeyColumn显式设置表， MapKeyColumn正确填充该键。 即：
@MapKeyColumn(name="PHONE_TYPE", table="EMP_PHONE")