Hibernate：外键的列数错误

我已经定义了我的两个实体类User和Permission之间的多对多关系。 用户具有username和countyId的主键组合，并且我的Permission表具有常规整数Id。 表UserPermission具有三个外键作为其主键：username，countyId和permissionId。

由于这是一个遗留数据库，我将无法使用Right Thing（™）并在User上创建一个整数主键。

我在User.class中定义了这样的多对多关系：

@ManyToMany(targetEntity=Permission.class, cascade={ CascadeType.PERSIST, CascadeType.MERGE } ) @JoinTable(name="tblUserPermission", joinColumns = { @JoinColumn(name="username"), @JoinColumn(name="countyId") }, inverseJoinColumns = { @JoinColumn(name="permissionId") }) private Collection permissions; 

Permission.class说：

 @ManyToMany( cascade = {CascadeType.PERSIST, CascadeType.MERGE}, mappedBy = "permissions", targetEntity = User.class ) private Collection users; 

我认为这是要走的路，但是当我启动使用Hibernate 3的Spring上下文时，我得到：

 Caused by: org.hibernate.AnnotationException: A Foreign key refering com.mydomain.data.entities.User from com.mydomain.data.entities.Permission has the wrong number of column. should be 1 

我的注释中我做错了什么？ 应该是2，而不是1。

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更新：

Arthur建议我添加referencedColumnName，但这给了我一个新的exception：

 Caused by: org.hibernate.AnnotationException: referencedColumnNames(username, countyId) of com.mydomain.data.entities.Permission.permissions referencing com.mydomain.data.entities.User not mapped to a single property 

根据他的请求，请遵循以下代码：Permission.Class：

 package com.mydomain.data.entities; import java.io.Serializable; import java.util.Collection; import javax.persistence.*; import org.hibernate.annotations.ForeignKey; @Entity @Table(name = "tblPermission") public class Permission extends PublishableEntityImpl implements Serializable, Cloneable { private static final long serialVersionUID = 7155322069731920447L; @Id @Column(name = "PermissionId", length = 8, nullable = false) private String PermissionId = ""; @ManyToOne(fetch=FetchType.LAZY) @JoinColumn(name = "CountyId", nullable = false) @ForeignKey(name="FK_CountyID") private County county; @Column(name = "Permission", nullable = true) private Integer permission = 1; @ManyToMany( cascade = {CascadeType.PERSIST, CascadeType.MERGE}, mappedBy = "Permissions", targetEntity = Item.class ) private Collection items; @ManyToMany( cascade = {CascadeType.PERSIST, CascadeType.MERGE}, mappedBy = "Permissions", targetEntity = User.class ) private Collection users; /** Getters and Setters **/ } 

和User.class

 package com.mydomain.data.entities; import java.util.*; import java.io.Serializable; import javax.persistence.*; import org.hibernate.annotations.ForeignKey; import org.hibernate.annotations.IndexColumn; import org.springframework.security.core.GrantedAuthority; import org.springframework.security.core.authority.GrantedAuthorityImpl; import org.springframework.security.core.userdetails.UserDetails; @Entity @Table(name = "tblUser") public class User extends PublishableEntityImpl implements Serializable, Cloneable { @Id @Column(name = "CountyId", nullable = false) private Integer countyId; @Id @Column(name = "Username", length = 25, nullable = false) private String username; @ManyToOne(fetch=FetchType.LAZY) @JoinColumn(name = "CountyId", nullable = false, insertable=false, updatable=false) @ForeignKey(name="FK_CountyID") private County county; @Column(name = "Name", length = 50, nullable = true) private String name; @Column(name = "Password", length = 30, nullable = true) private String password; @Column(name = "Role", nullable = false) private Integer role; @ManyToMany(targetEntity=Permission.class, cascade={ CascadeType.PERSIST, CascadeType.MERGE } ) @JoinTable(name="tblUserPermission", joinColumns = { @JoinColumn(name="Username", referencedColumnName="Username"), @JoinColumn(name="CountyId", referencedColumnName="CountyId") }, inverseJoinColumns = { @JoinColumn(name="PermissionId", referencedColumnName="PermissionId") }) private Collection permissions; @OneToMany(fetch=FetchType.LAZY, mappedBy="county") @IndexColumn(name="version") private List versions; /** Getters and setters **/ } 

干杯

聂

Answer 1

为了解决referencedColumnNameexception

在用户放

 @ManyToMany(cascade={CascadeType.PERSIST, cascadeType.MERGE}) private Collection permissions; 

并在权限

 @ManyToMany(mappedBy="permissions") @JoinTable(name="tblUserPermission", joinColumns={@JoinColumn(name="permissionId", referencedColumnName="permissionId")}, inverseJoinColumns={ @JoinColumn(name="username", referencedColumnName="username"), @JoinColumn(name="countyId", referencedColumnName="countyId")}) private Collection users; 

UserId类

 public class UserId implements Serializable { private String username; private Integer countyId; // getter's and setter's public boolean equals(Object o) { if(o == null) return false; if(!(o instanceof UserId)) return false; UserId id = (UserId) o; if(!(getUsername().equals(id.getUsername())) return false; if(!(getCountyId().equals(id.getCountyId())) return false; return true; } public int hachcode() { // hashcode } } 

然后在User类中输入

 @Entity @Table(name="tblUser") @IdClass(UserId.class) public class User ... { @Id private String username; @Id private Integer countyId; } 

问候，