使用正则表达式从字符串中提取IP地址

在应用程序中，我得到包含IP地址的字符串，但这些字符串没有精确的格式。 我们所知道的是这些字符串可能包含IP地址。

这是一个字符串可以是什么样子的例子：

• “XPSPort”
• “IP_10.29.167.187”
• “10.29.166.193”

我想获得一个Java代码，如果有一个字符串，则提取字符串的ip地址，如果字符串不包含ip地址，则返回“”。

我试过这段代码，但它不起作用：

String IPADDRESS_PATTERN = "^([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." + "([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." + "([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." + "([01]?\\d\\d?|2[0-4]\\d|25[0-5])$"; Pattern pattern = Pattern.compile(IPADDRESS_PATTERN); Matcher matcher = pattern.matcher(ipString); if (matcher.find()) { return matcher.group(); } else{ return "0.0.0.0"; } 

我很确定使用RegExp是实现这一目标的最佳方式，但我对这些并不是很好，所以有人能帮我找到好的RegExp吗？

提前致谢。

Answer 1

理查德的链接帮助我找到答案。 这是工作代码：

 String IPADDRESS_PATTERN = "(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)"; Pattern pattern = Pattern.compile(IPADDRESS_PATTERN); Matcher matcher = pattern.matcher(ipString); if (matcher.find()) { return matcher.group(); } else{ return "0.0.0.0"; } 

Answer 2

IPV4_PATTERN = "^(25[0-5]|2[0-4]\\d|[0-1]?\\d?\\d)(\\.(25[0-5]|2[0-4]\\d|[0-1]?\\d?\\d)){3}$"

Answer 3

检查此解决方案以validationIPV4和IPV6地址 。

 /** * This class provides a variety of basic utility methods that are not * dependent on any other classes within the org.jamwiki package structure. */ public class Utilities { private static Pattern VALID_IPV4_PATTERN = null; private static Pattern VALID_IPV6_PATTERN = null; private static final String ipv4Pattern = "(([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.){3}([01]?\\d\\d?|2[0-4]\\d|25[0-5])"; private static final String ipv6Pattern = "([0-9a-f]{1,4}:){7}([0-9a-f]){1,4}"; static { try { VALID_IPV4_PATTERN = Pattern.compile(ipv4Pattern, Pattern.CASE_INSENSITIVE); VALID_IPV6_PATTERN = Pattern.compile(ipv6Pattern, Pattern.CASE_INSENSITIVE); } catch (PatternSyntaxException e) { //logger.severe("Unable to compile pattern", e); } } /** * Determine if the given string is a valid IPv4 or IPv6 address. This method * uses pattern matching to see if the given string could be a valid IP address. * * @param ipAddress A string that is to be examined to verify whether or not * it could be a valid IP address. * @return true if the string is a value that is a valid IP address, * false otherwise. */ public static boolean isIpAddress(String ipAddress) { Matcher m1 = Utilities.VALID_IPV4_PATTERN.matcher(ipAddress); if (m1.matches()) { return true; } Matcher m2 = Utilities.VALID_IPV6_PATTERN.matcher(ipAddress); return m2.matches(); } } 

source： 确定给定字符串是否为有效的IPv4或IPv6地址。

Answer 4

IP地址正则表达式模式：

 ^([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\. ([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.([01]?\\d\\d?|2[0-4]\\d|25[0-5])$ 

有关示例的参考，请单击此处