使用java从jar作为资源播放.wav文件
我想使用java代码播放.wav文件，该代码在jar文件中作为资源。 我的代码看起来像这样 –
try { URL defaultSound = getClass().getResource("/images/ads/WindowsNavigationStart.wav"); // getClass().getSy.getResource("/images/ads/WindowsNavigationStart.wav"); File soundFile = new File(defaultSound.toURI()); AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(soundFile); Clip clip = AudioSystem.getClip(); clip.open(audioInputStream); clip.start( ); } catch (Exception ex) { ex.printStackTrace(); } WindowsNavigationStart.wav文件存在于我的一个jar文件中。 但得到以下例外 –
java.lang.IllegalArgumentException: URI is not hierarchical at java.io.File.(File.java:363) at au.com.webscan.wwwizard.app.admin.customfile.UpOneLevelFolder.btnUpFolderActionPerformed(Unknown Source) at au.com.webscan.wwwizard.app.admin.customfile.UpOneLevelFolder.access$000(Unknown Source) at au.com.webscan.wwwizard.app.admin.customfile.UpOneLevelFolder$1.actionPerformed(Unknown Source) at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:1995) at javax.swing.AbstractButton$Handler.actionPerformed(AbstractButton.java:2318) at javax.swing.DefaultButtonModel.fireActionPerformed(DefaultButtonModel.java:387) at javax.swing.DefaultButtonModel.setPressed(DefaultButtonModel.java:242) at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(BasicButtonListener.java:236) at java.awt.AWTEventMulticaster.mouseReleased(AWTEventMulticaster.java:272) at java.awt.Component.processMouseEvent(Component.java:6288) at javax.swing.JComponent.processMouseEvent(JComponent.java:3267) at java.awt.Component.processEvent(Component.java:6053) at java.awt.Container.processEvent(Container.java:2041) at java.awt.Component.dispatchEventImpl(Component.java:4651) at java.awt.Container.dispatchEventImpl(Container.java:2099) at java.awt.Component.dispatchEvent(Component.java:4481) at java.awt.LightweightDispatcher.retargetMouseEvent(Container.java:4577) at java.awt.LightweightDispatcher.processMouseEvent(Container.java:4238) at java.awt.LightweightDispatcher.dispatchEvent(Container.java:4168) at java.awt.Container.dispatchEventImpl(Container.java:2085) at java.awt.Window.dispatchEventImpl(Window.java:2478) at java.awt.Component.dispatchEvent(Component.java:4481) at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:643) at java.awt.EventQueue.access$000(EventQueue.java:84) at java.awt.EventQueue$1.run(EventQueue.java:602) at java.awt.EventQueue$1.run(EventQueue.java:600) at java.security.AccessController.doPrivileged(Native Method) at java.security.AccessControlContext$1.doIntersectionPrivilege(AccessControlContext.java:87) at java.security.AccessControlContext$1.doIntersectionPrivilege(AccessControlContext.java:98) at java.awt.EventQueue$2.run(EventQueue.java:616) at java.awt.EventQueue$2.run(EventQueue.java:614) at java.security.AccessController.doPrivileged(Native Method) at java.security.AccessControlContext$1.doIntersectionPrivilege(AccessControlContext.java:87) at java.awt.EventQueue.dispatchEvent(EventQueue.java:613) at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:269) at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:184) at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:174) at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:169) at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:161) at java.awt.EventDispatchThread.run(EventDispatchThread.java:122)
请给我一个解决方案。 谢谢你们。
更改：
AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(soundFile);
至：
System.out.println("defaultSound " + defaultSound); // check the URL! AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(defaultSound);
你有没有尝试过：
InputStream is= getClass().getResourceAsStream("/images/ads/WindowsNavigationStart.wav"); AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(is);
基本上我认为你不能在jar文件中的URI中创建一个文件。 但是您可以直接传递输入流。
使用Class.getResourceAsStream（）
获得inputStream的句柄后，获取audioInputStream并完成剩下的工作。
InputStream is = getClass().getResourceAsStream("......"); AudioInputStream ais = AudioSystem.getAudioInputStream(is); Clip clip = AudioSystem.getClip(); clip.open(ais);
完美解决方案…….
URL url = this.getClass().getResource("sounds/beep.au"); String urls=url.toString(); urls=urls.replaceFirst("file:/", "file:///"); AudioClip ac=Applet.newAudioClip(new URL(urls)); ac.play();
在制作单jar java应用程序时，请参考我之前的回答。 标题是误导性的，但海报试图做一些几乎与你相同的事情。 一些最佳细节位于聊天记录的链接中。
try { AudioPlayer.player.start(new AudioStream(getClass().getResourceAsStream("/sound/SystemNotification.wav"))); } catch (Exception e) { e.printStackTrace(); }
这对我来说很好：
public void playSound() { InputStream in; try { in = new BufferedInputStream(new FileInputStream(new File( getClass().getClassLoader() .getResource("com/kaito/resources/sound.wav").getPath()))); AudioStream audioStream = new AudioStream(in); AudioPlayer.player.start(audioStream); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } }
以下允许我在Eclipse项目和导出的jar文件中播放声音：
– 注意使用BufferedInputStream
– 注意，使用inputStream而不是file。
在我的main（）中：
playAlarmSound();
在我class上：
public static void playAlarmSound() { ClassLoader classLoader = App.class.getClassLoader(); InputStream inputStream = classLoader.getResourceAsStream("alarmsound.wav"); try { Clip clip = AudioSystem.getClip(); AudioInputStream ais = AudioSystem.getAudioInputStream(new BufferedInputStream(inputStream)); clip.open(ais); clip.start(); } catch (IOException | LineUnavailableException | UnsupportedAudioFileException e) { System.err.println("ERROR: Playing sound has failed"); e.printStackTrace(); } }
像Kal写道：
- InputStream是= getClass（）。getResourceAsStream（“……”）;
- AudioInputStream ais = AudioSystem.getAudioInputStream（is）; …
我做到了这一点，它起初没有用，但“java.io.IOException”的问题是我使用了File.separator，由于某种原因，win 8.1无法处理“\\”……
public AudioInputStream getSound(String fileName){ InputStream inputSound; AudioInputStream audioInStr; String fs = File.separator; try { absolutePath = fs +packageName+ fs +folderName+ fs +fileName; inputSound = getClass().getResourceAsStream(absolutePath); //if null pointer exception try unix, for some reason \\ doesn't work on win 8.1 if(inputSound == null) { absolutePath = "/" + packageName + "/" + folderName + "/" + fileName; inputSound = getClass().getResourceAsStream(absolutePath); } audioInStr = AudioSystem.getAudioInputStream(new BufferedInputStream(inputSound)); return audioInStr; }