如何确定特定时间周五和周日之间的日期
我正在尝试检查当前日期和时间是在星期五17:42到星期日17:42之间的Java。
目前我正在用非常糟糕的代码块来做这件事。 这是一个匆忙的解决方案。 现在我正在重构，但我在joda等找不到任何方法。
有任何想法吗？ 谢谢
private final Calendar currentDate = Calendar.getInstance(); private final int day = currentDate.get(Calendar.DAY_OF_WEEK); private final int hour = currentDate.get(Calendar.HOUR_OF_DAY); private final int minute = currentDate.get(Calendar.MINUTE); if (day != 1 && day != 6 && day != 7) { if (combined != 0) { return badge == 1; } else { return badge == product; } } else { if (day == 6 && hour > 16) { if (hour == 17 && minute < 43) { if (combined != 0) { return badge == 1; } else { return badge == product; } } else { return badge == 0; } } else if (day == 6 && hour 16) { if (hour == 17 && minute < 43) { return badge == 0; } else { if (combined != 0) { return badge == 1; } else { return badge == product; } } } else { return badge == 0; } } 在@MadProgrammer和@Meno Hochschild的帮助下，我使用了这样的解决方案
方法：
public static boolean isBetween(LocalDateTime check, LocalDateTime startTime, LocalDateTime endTime) { return ((check.equals(startTime) || check.isAfter(startTime)) && (check.equals(endTime) || check.isBefore(endTime))); }
用法：
static LocalDateTime now = LocalDateTime.now(); static LocalDateTime friday = now.with(DayOfWeek.FRIDAY).toLocalDate().atTime(17, 41); static LocalDateTime sunday = friday.plusDays(2).plusMinutes(1); if (!isBetween(now, friday, sunday)) { ... }
再次感谢您的努力。
Date和Calendar具有可以在Date / Calendar ， equals ， before和after其他实例上执行比较的方法
但是，我鼓励使用Java 8的新Time API
public static boolean isBetween(LocalDateTime check, LocalDateTime startTime, LocalDateTime endTime) { return ((check.equals(startTime) || check.isAfter(startTime)) && (check.equals(endTime) || check.isBefore(endTime))); }
如果提供的LocalDateTime包含在指定范围内，则返回true 。
就像是…
LocalDateTime start = LocalDateTime.now(); start = start.withDayOfMonth(26).withHour(17).withMinute(42).withSecond(0).withNano(0); LocalDateTime end = start.plusDays(2); LocalDateTime check = LocalDateTime.now(); System.out.println(check + " is within range = " + isBetween(check, start, end)); check = start; System.out.println(check + " is within range = " + isBetween(check, start, end)); check = end; System.out.println(check + " is within range = " + isBetween(check, start, end)); check = start.plusDays(1); System.out.println(check + " is within range = " + isBetween(check, start, end)); check = end.plusMinutes(1); System.out.println(check + " is within range = " + isBetween(check, start, end));
哪个输出
2015-06-25T18:31:32.969 is within range = false 2015-06-26T17:42 is within range = true 2015-06-28T17:42 is within range = true 2015-06-27T17:42 is within range = true 2015-06-28T17:43 is within range = false
Joda-Time有一个Interval课程，使它更加稳定
Interval targetInterval = new Interval(targetStart, targetEnd); System.out.println("Contains interval = " + interval.contains(targetInterval)
这是在这里展示的
一种不同的方法……
所以我想回家的路上，假设你所拥有的是你要检查的日期/时间，你如何确定这一天是否在你的范围内
LocalDateTime now = LocalDateTime.now(); boolean isBetween = false; switch (now.getDayOfWeek()) { case FRIDAY: case SATURDAY: case SUNDAY: LocalDateTime lastFriday = getLastFriday(now); LocalDateTime nextSunday = getNextSunday(now); isBetween = isBetween(now, lastFriday, nextSunday); System.out.println(lastFriday + " - " + nextSunday + ": " + end); break; }
这样做是检查dayOfWeek以查看它是否在所需范围内，如果是，它会从指定日期找到上一个Friday和下个星期Sunday ，并检查它是否介于它们之间（参见上一个示例）
lastFriday和nextSunday只是从指定的日期/时间添加/减去day ，直到达到所需的dayOfWeek ，然后播种所需的时间限制
public static LocalDateTime getLastFriday(LocalDateTime anchor) { LocalDateTime ldt = LocalDateTime.from(anchor); return ldt.with(DayOfWeek.FRIDAY).withHour(17).withMinute(42).withSecond(0).withNano(0); } public static LocalDateTime getNextSunday(LocalDateTime anchor) { LocalDateTime ldt = LocalDateTime.from(anchor); return ldt.with(DayOfWeek.SUNDAY).withHour(17).withMinute(42).withSecond(0).withNano(0); }
使用Calendar您可以知道DAY_OF_WEEK是给定日期的内容，然后只需查看小时数：
Calendar c = Calendar.getInstance(); int dayOfWeek = c.get(Calendar.DAY_OF_WEEK); int hour = c.get(Calendar.HOUR_OF_DAY); int minute = c.get(Calendar.MINUTE); // in friday the hour must be greater than 17:42 if (dayOfWeek == 5 && ((hour > 17) || (hour == 17 && minute >= 42)) { // successss!! } // days from 1 to 7... saturday(6) all day if (dayOfWeek == 6) { // successss!! } // sunday hour must be lower than 17:42 if (dayOfWeek == 7 && ((hour < 17) || (hour == 17 && minute <= 42)) { // successss!! }
使用旧Java的更好解决方案如下所示：
// current timestamp GregorianCalendar gcal = new GregorianCalendar(); // specify ISO-week (you are searching for friday until sunday in this order) gcal.setMinimalDaysInFirstWeek(4); gcal.setFirstDayOfWeek(Calendar.MONDAY); // sunday at 17:43 GregorianCalendar sunday = (GregorianCalendar) gcal.clone(); sunday.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY); sunday.set(Calendar.HOUR_OF_DAY, 17); sunday.set(Calendar.MINUTE, 43); sunday.set(Calendar.SECOND, 0); sunday.set(Calendar.MILLISECOND, 0); // friday at 17:42 GregorianCalendar friday = (GregorianCalendar) sunday.clone(); friday.add(Calendar.DATE, -2); friday.add(Calendar.MINUTE, -1); // logging for test purposes SimpleDateFormat f = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS"); System.out.println(f.format(friday.getTime())); System.out.println(f.format(gcal.getTime())); System.out.println(f.format(sunday.getTime())); // result (assumption: half-open-interval) boolean withinTimeWindow = !gcal.before(friday) && gcal.before(sunday);
Java-8提供了一种更短的方法（假设ISO-weekmodel）：
LocalDateTime now = LocalDateTime.now(); LocalDateTime friday = now.with(DayOfWeek.FRIDAY).toLocalDate().atTime(17, 42); LocalDateTime sunday = friday.plusDays(2).plusMinutes(1); boolean withinTimeWindow = !now.isBefore(friday) && now.isBefore(sunday);
最后，您的等效评估可能如下所示：
if (!withinTimeWindow) { if (combined != 0) { return badge == 1; } else { return badge == product; } } else { return badge == 0; }