Java中的后续HTTPS POST请求，保留了cookie
我需要获取HTTPS URL的输入流，例如。 https://baseurl.com/mypdfgenerated.php?param=somevalue 。 为了访问此URL，我需要通过提供BODY参数来浏览登录页面（例如https://baseurl.com/login.php ）：
user_name, web_pwd and submit_login 我假设成功访问第一个URL的唯一方法是通过POST到/login.php，然后存储cookie，然后在下一个GET请求中重用cookie-session-ID; 如果这是正确的方法，那么有人可以请与正确/最近的库共享解决方案吗？
不确定哪种方法最好，但帮助我实现这一目的的是CloseableHttpClient类，它与BasicCookieStore一起为登录后的请求保留cookie，实现如下：
BasicCookieStore cookieStore = new BasicCookieStore(); CloseableHttpClient httpclient = HttpClients.custom().setDefaultCookieStore(cookieStore).build(); HttpUriRequest login = RequestBuilder.post() .setUri(new URI(url_login)) .addParameter("login", "loginuname") .addParameter("password", "pwd") .addParameter("submit", "sub_mit"); CloseableHttpResponse response = httpclient.execute(login); List cookies = cookieStore.getCookies(); response.close(); HttpGet httpget2 = new HttpGet(url_to_get_after_login); CloseableHttpResponse response2 = httpclient.execute(httpget2); response2.close();
Java Samples中的示例代码段
try { System.setProperty("java.protocol.handler.pkgs", "com.sun.net.ssl.internal.www.protocol"); java.security.Security.addProvider(new com.sun.net.ssl.internal.ssl.Provider()); URL url = new URL("https://www.yourwebsite.com/"); // Some URL HttpsURLConnection connection = (HttpsURLConnection) url.openConnection(); connection.setDoInput(true); connection.setDoOutput(true); connection.setRequestMethod("POST"); connection.setFollowRedirects(true); String query = "UserID=" + URLEncoder.encode("username"); query += "&"; query += "password=" + URLEncoder.encode("password"); query += "&"; // open up the output stream of the connection DataOutputStream output = new DataOutputStream( connection.getOutputStream() ); // write out the data output.writeBytes( query ); }catch(Exception err){ err.printStackTrace(); }
看看cookies的用法
您应该使用一个为您处理cookie的库，例如Apache HTTPClient 。