xstream CannotResolveClassException

我正在尝试使用xstream 1.4.2将xml转换为对象。 它确实对我来说非常好，直到我将对象的类文件放在一个单独的包中，而不是主代码运行的位置。 然后我得到一个CannotResolveClassException。 我尝试过使用其他人推荐的setClassLoader方法，但这没有用。

Exception in thread "main" com.thoughtworks.xstream.mapper.CannotResolveClassException: result at com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:56) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.DynamicProxyMapper.realClass(DynamicProxyMapper.java:55) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.PackageAliasingMapper.realClass(PackageAliasingMapper.java:88) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.ClassAliasingMapper.realClass(ClassAliasingMapper.java:79) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.ArrayMapper.realClass(ArrayMapper.java:74) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.CachingMapper.realClass(CachingMapper.java:45) at com.thoughtworks.xstream.core.util.HierarchicalStreams.readClassType(HierarchicalStreams.java:29) at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:133) at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32) at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1052) at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1036) at com.thoughtworks.xstream.XStream.fromXML(XStream.java:912) at com.thoughtworks.xstream.XStream.fromXML(XStream.java:903) at main.readClass(main.java:48) at main.main(main.java:28) 

答案： xstream期望xml结构相对于它（对象）所源自的包。 因此必须使用xstream.alias才能为xml结构添加别名。

 xstream.alias("something", Something.class); 

否则xstream将期望“Something”在默认包中，而不是它所属的包。

Answer 1

将类名传递给别名方法时，需要传递完全限定的类名，即类名及其包名。

示例：假设如果类Something在com.xyz包中，那么您需要传递com.xyz.Something.class作为参数

谢谢

Answer 2

对于你的问题，这将是有用的

下载Xtream.jar

 package businessfunctions; import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.util.List; import java.util.concurrent.TimeUnit; import objectrepository.LoginPojo; import objectrepository.LoginPojos; import org.openqa.selenium.By; import org.openqa.selenium.WebDriver; import org.openqa.selenium.WebElement; import org.openqa.selenium.firefox.FirefoxDriver; import com.thoughtworks.xstream.XStream; import com.thoughtworks.xstream.io.xml.DomDriver; public void readRepository(String fNmae){ // Instantiate XStream Object XStream xstream = new XStream(new DomDriver()); // Set Person class into xstream alias xstream.alias("loginpojos",LoginPojos.class); xstream.alias("loginpojo",LoginPojo.class); xstream.addImplicitCollection(LoginPojos.class, "loginpojos"); // Create a StringBuffer var StringBuffer contents = new StringBuffer(); try { // TODO Auto-generated method stub // Set BufferReader var "in" to read from PersonXML.xml file BufferedReader in = new BufferedReader(new FileReader(repoPath+fNmae)); String str; while ((str = in.readLine()) != null) { contents.append(str); } in.close(); } catch (IOException e) { System.out.println(e.toString()); } // Checking the StringBuffer variable "contents" System.out.println(contents); String content = new String(); // Put all the contents from contents to String variable content --xstream.fromXML()takes //only String content = contents.toString(); // Convert content into XML and change and set to obj newPerson of class Person LoginPojos loginPojosList = (LoginPojos)xstream.fromXML(content); List loginPojoList = loginPojosList.getLoginpojos(); for(LoginPojo newLogiPojo:loginPojoList){ // Print out the newPerson properties System.out.println("Property Label: " + newLogiPojo.getPropLabel()); System.out.println("Property Name: " + newLogiPojo.getPropName()); System.out.println("Property Value: " + newLogiPojo.getPropValue()); } } public static void main(String args[]) { try { DriverSetup ds= new DriverSetup(); ds.readRepository("login.xml"); }catch(Exception e){ e.printStackTrace(); } package objectrepository; import java.util.ArrayList; import java.util.List; public class LoginPojos { public List loginpojos = new ArrayList(); public List getLoginpojos() { return loginpojos; } public void setLoginpojos(List loginpojos) { this.loginpojos = loginpojos; } } package objectrepository; public class LoginPojo { private String propLabel; private String propName; private String propValue; public String getPropLabel() { return propLabel; } public void setPropLabel(String propLabel) { this.propLabel = propLabel; } public String getPropName() { return propName; } public void setPropName(String propName) { this.propName = propName; } public String getPropValue() { return propValue; } public void setPropValue(String propValue) { this.propValue = propValue; } }   User name1 id1 username1   User name id username   

Answer 3

花了半个晚上试图解决类似的错误。
将驱动程序传递给xStream奇迹般地帮助了。

 XStream xstream = new XStream(new StaxDriver());