TicTacToe Game的Java代码

我正在尝试使用数组等创建一个简单的tic tac toe游戏作为练习。 只是一个小项目,我正在为自己工作。 我知道如何编写下面的代码,但我仍然坚持如何让数组输入改变为x或o的每个用户输入。

import java.util.Scanner; public class TicTacToe { public static void main(String[] args) { Scanner input = new Scanner(System.in); String[] array; array = new String [9]; int uInput; int pCounter=1; while ( uInput <= 9) { System.out.println("Enter X coordinate:"); uInput = input.nextInt(); array[uInput] = ("x"); System.out.println("Enter X coordinate:"); uInput = input.nextInt(); array[uInput] = ("o"); for (int yCounter = 0; yCounter < 6; yCounter++) { System.out.print("--"); } System.out.println(); for (int fCounter=0; fCounter<(3); fCounter++) { for (int xCounter=0; xCounter<1; xCounter++) { for (pCounter=1; pCounter<4; pCounter++) { System.out.printf(" %d| ", array[pCounter]); } } } System.out.println(); for (int zCounter=0; zCounter<4; zCounter++) { System.out.print("---"); } System.out.println(); } System.out.print("0 1 2\n3 4 5\n6 7 8\n"); } } 

逻辑应该是那样的(伪代码):

 boolean win = false, tie = false; String winner = ""; while(!win && !tie){ getInputFromUser1(); updateBoard(); if (win || tie) break; getInputFromUser2(); updateBoard(); } //check if win or tie and display message respectfully displayEndMessage(); return;