如何在android中将video文件（.mp4）格式转换为二进制格式？

我想在网络服务器上传video。 我得到了服务，我想以二进制格式传递文件，我该怎么办？

我试图在base64的帮助下将video文件转换为二进制格式..？

public class binaryformat extends Activity { private String strAttachmentCoded; Button b1; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); b1=(Button)findViewById(R.id.button1); b1.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub File file = new File("/mnt/sdcard/C:/Program Files (x86)/Wowza Media Systems/Wowza Media Server 3.1.2/content/sample.mp4"); FileInputStream objFileIS = null; try { objFileIS = new FileInputStream(file); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } ByteArrayOutputStream objByteArrayOS = new ByteArrayOutputStream(); byte[] byteBufferString = new byte[1024]; try { for (int readNum; (readNum = objFileIS.read(byteBufferString)) != -1;) { objByteArrayOS.write(byteBufferString, 0, readNum); System.out.println("read " + readNum + " bytes,"); } } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } byte[] byteBinaryData = Base64.encode((objByteArrayOS.toByteArray()), Base64.DEFAULT); strAttachmentCoded = new String(byteBinaryData); } }); } 

}

Answer 1

我在我的3应用程序中遇到过使用XML通过服务器发送IMAGE或VIDEO是好的。 如果要在ANDROID中上传图像或video，最好以XML格式在base64中发送IMAGE或VIDEO。

 public static String uploadMultiplePhoto(String url, String xmlString) { String responseString = ""; try { //instantiates httpclient to make request DefaultHttpClient httpclient = new DefaultHttpClient(); //url with the post data HttpPost request = new HttpPost(url); //convert parameters into JSON object //JSONObject holder = new JSONObject(jsonObjString); //passes the results to a string builder/entity StringEntity se = new StringEntity(xmlString); //sets the post request as the resulting string request.setEntity(se); //sets a request header so the page receving the request //will know what to do with it request.setHeader("Accept", "application/xml"); /*request.setHeader("Content-type", "application/xml");*/ //Handles what is returned from the page ResponseHandler responseHandler = new BasicResponseHandler(); responseString = httpclient.execute(request, responseHandler); } catch (Exception exception) { exception.printStackTrace(); } return responseString; }