python AES加密java解密

我有超过1000张需要加密的图片和video。 顶部只是简单的东西,我想使用AES,但我无法弄清楚如何在我的计算机上加密然后解密设备上的项目。

我将使用python加密计算机上的所有项目。 然后在一个随需应变的时尚将使用java解密该项目(Android应用程序)

任何简单的解释都会做伪代码也很好。

我遇到的主要问题是如何使用相同的密钥进行加密和解密。 我一直在生成密钥,无法将其移植到其他设备进行解密。

谢谢

Python代码。 Works加密和解密。

from Crypto.Cipher import AES import os, random, struct key = '0123456789abcdef' mode = AES.MODE_CBC chunksize = 64*1024 iv = ''.join(chr(random.randint(0,0xFF)) for i in range(16)) encryptor = AES.new(key,mode,iv) filesize = os.path.getsize('sample.jpg') with open('sample.jpg','rb') as infile: with open('sample.enc','wb') as outfile: outfile.write(struct.pack('<Q',filesize)) outfile.write(iv) while True: chunk = infile.read(chunksize) if len(chunk) == 0: break elif len(chunk) % 16 != 0: chunk += ' ' * (16 - len(chunk) % 16) outfile.write(encryptor.encrypt(chunk)) ## decrypt with open('sample.enc', 'rb') as infile: origsize = struct.unpack('<Q', infile.read(struct.calcsize('Q')))[0] iv = infile.read(16) decryptor = AES.new(key, AES.MODE_CBC, iv) with open('sample2.jpg', 'wb') as outfile: while True: chunk = infile.read(chunksize) if len(chunk) == 0: break outfile.write(decryptor.decrypt(chunk)) outfile.truncate(origsize) 

我如何在Java中执行解密部分? 这是我快速草率的Java代码,不起作用。 我认为这是填充物搞砸了。

  public void decryptFile(){ String inFile = "sample.enc"; String outFile = "sample.jpg"; String dir = Environment.getExternalStorageDirectory() +"/Android/data/HOT/"; InputStream is ; byte[] iv = new byte[16]; try { is = new FileInputStream(dir+inFile); is.read(iv); } catch (FileNotFoundException e1) { // TODO Auto-generated catch block Log.d("D1","no file found"); } catch (IOException e) { // TODO Auto-generated catch block Log.d("D-2","no file found"); e.printStackTrace(); } byte[] k = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'}; Key key = new SecretKeySpec(k,"AES"); try { Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding"); cipher.init(Cipher.DECRYPT_MODE, key,new IvParameterSpec(iv)); OutputStream outs = new FileOutputStream(dir+outFile); is = new FileInputStream(dir+inFile); while(true){ byte[] chunk = new byte[64*1024]; is.read(chunk); if(chunk.length == 0){ break; } outs.write(cipher.doFinal(chunk)); } } catch (NoSuchAlgorithmException e) { // TODO Auto-generated catch block Log.d("D","1"); e.printStackTrace(); } catch (NoSuchPaddingException e) { // TODO Auto-generated catch block Log.d("D","2"); e.printStackTrace(); } catch (InvalidKeyException e) { // TODO Auto-generated catch block Log.d("D","3"); e.printStackTrace(); } catch (InvalidAlgorithmParameterException e) { // TODO Auto-generated catch block Log.d("D","4"); e.printStackTrace(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block Log.d("D","5"); e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block Log.d("D","6"); e.printStackTrace(); } catch (IllegalBlockSizeException e) { // TODO Auto-generated catch block Log.d("D","7"); e.printStackTrace(); } catch (BadPaddingException e) { // TODO Auto-generated catch block Log.d("D","8"); e.printStackTrace(); } ImageView im = (ImageView)findViewById(R.id.imageView2); Bitmap mainBitmap = BitmapFactory.decodeFile(dir+outFile); im.setImageBitmap(mainBitmap); } 

在Java版本中,与Python版本不同,在读取IV之前,您似乎没有读取文件大小。

您还打开第二个FileInputStream ,然后在读取Cipher块之前不要跳过filesize和IV。

要检查的另一件事是Java和Python中的键被解释相同,即Python中的字符串与Java中的字节数组产生相同的字节序列。